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Ludmilka [50]
2 years ago
12

What are the following of this function y = 4sin (2( x -

xFormula1" title="\frac{3\pi }{4}" alt="\frac{3\pi }{4}" align="absmiddle" class="latex-formula"> )) :
amplitude
minimum
maximum
period
phase shift
midline equation
Mathematics
1 answer:
Andrei [34K]2 years ago
6 0

Answer:

See below...

Step-by-step explanation:

For a function whose formula is in this pattern:

y=A\sin\left(B(x-C)\right)

Amplitude: |A|

Period: \frac{2\pi}{B}

Phase Shift:  C

In this question, A=4,\,B=2,\,C=\frac{3\pi}{4}

Amplitude: 4

Period: \frac{2\pi}{2}=\pi

Phase Shift: \frac{3\pi}{4}

There is no vertical shift, so the midline is the x-axis whose equation is y = 0.

Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.

The graph is attached.

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Three ratios equivalent to 16:12
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Answer:

48:36   64:48  60:80

Step-by-step explanation:

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Use the tens frame to help you solve the problem below 8+4×10
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Instead i use pemdas so the answer to this problem would be 48 
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72 is equal to 80% of a number n. Write and solve and equation to find n. Write the percent as a decimal
muminat

Hey there!!

80% = 80/100 = 0.8

80% of 'n' = 72

0.8n=72

n = 72/0.8

n = 90

Hence, the number is 80!

Hope it helps!


6 0
2 years ago
Amy and her brother get the same allowance. Amy saved 1/5 and her brother 4/5 of his allowance. How much more did her brother sa
Anon25 [30]

Answer:

3/5

Step-by-step explanation:

Step one:

given data

Amy saved 1/5

her brother 4/5

Required

How much more did her brother save

Step two:

let us subtract Amy's savings from her brother's

4/5-1/5

=4-1/5

=3/5

6 0
2 years ago
Find the midpoint of the segment with the following endpoints.<br> (-3,6) and (3, 0)
otez555 [7]

The midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

<h3>Midpoint of a line </h3>

From the question, we are to determine the midpoint of the segment with the given endpoints

The given endpoints are

(-3,6) and (3, 0)

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

Thus,

The midpoint of the line with the endpoints (-3,6) and (3, 0) is

((-3+3)/2, (6+0/2)

= (0/2, 6/2)

= (0, 3)

Hence, the midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

Learn more on Midpoint of a line here: brainly.com/question/18315903

#SPJ1

3 0
1 year ago
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