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Ludmilka [50]
3 years ago
12

What are the following of this function y = 4sin (2( x -

xFormula1" title="\frac{3\pi }{4}" alt="\frac{3\pi }{4}" align="absmiddle" class="latex-formula"> )) :
amplitude
minimum
maximum
period
phase shift
midline equation
Mathematics
1 answer:
Andrei [34K]3 years ago
6 0

Answer:

See below...

Step-by-step explanation:

For a function whose formula is in this pattern:

y=A\sin\left(B(x-C)\right)

Amplitude: |A|

Period: \frac{2\pi}{B}

Phase Shift:  C

In this question, A=4,\,B=2,\,C=\frac{3\pi}{4}

Amplitude: 4

Period: \frac{2\pi}{2}=\pi

Phase Shift: \frac{3\pi}{4}

There is no vertical shift, so the midline is the x-axis whose equation is y = 0.

Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.

The graph is attached.

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Answer:

Step-by-step explanation:

6.1 / 5 ( 12b + 5 )

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7 0
3 years ago
20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

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z−2(x+5)=

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