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3 years ago

Question here I need help with this

Mathematics

2 answers:

NeTakaya3 years ago

8 0

cool can i have brainliest

Elza [17]3 years ago

3 0

Answer: nice the answer is ummmm I don’t know

Step-by-step explanation:

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Solve 2 + 2x = 3 + 2x using Inverse operations. How does the algebralc result show you that there is no solution?

BabaBlast [244]

Answer:

0=1

Step-by-step explanation:

Solve 2 + 2x = 3 + 2x using Inverse operations. How does the algebralc result show you that there is no solution

8 0

3 years ago

The diagonal of a TV screen is 26 inches. The screen is 18.8 inches wide. How high is the screen? Round to the nearest hundredth

cluponka [151]

26^2 = 18.8^2 + H^2
H^2 = 322.56
H = 17.96 inches

8 0

4 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

Cynthia invested $12,000 in a savings account. If the interest rate is 6%, how much will be in the account in 10 years by compou

sattari [20]

Answer:

In 10 years she'll have approximately $21865.4 in her account.

Step-by-step explanation:

When an amount is compounded continuously its value over time is given by the following expression:

$v(t) = v(0)*e^{rt}$

Applying data from the problem gives us:

$v(10) = 12000*e^{(0.06*10)}\\v(10) = 12000*e^{0.6}\\v(10) = 21865.4$

In 10 years she'll have approximately $21865.4 in her account.

6 0

3 years ago

Read 2 more answers

Find (a) the amplitude, (b) the wavelength, (c) the period, and (d) the speed of a wave whose displacement is given by y= 1.5 co

leonid [27]

Answer with Step-by-step explanation:

We are given that displacement of wave

$y=1.5cos(0.68x+37t)$

Where y in cm and t in sec.

a.Compare it with

$y=Acos(kx+\omega t)$

Amplitude of wave=A

We get A=1.5

Amplitude=A=1.5 cm

b.k=0.68

$\frac{2\pi}{\lambda}=0.68$

$\lambda=\frac{2\times 3.14}{0.68}=9.2 cm$

Using $\pi=3.14$

Wavelength of the wave=9.2 cm

c.Period= $\frac{2\pi}{T}=\omega$

$\frac{2\pi}{T}=37$

$T=\frac{2\times 3.14}{37}=0.17 s$

The period of the wave=0.17 s

Speed of the wave= $\nu \lambda=\frac{\lambda}{T}=\frac{9.2}{0.17}$

Speed of the wave=54.1 cm/s

8 0

3 years ago