Answer:
triangle DCA is congruent to triangle BAC - because of AAS (angle-angle-side) theorem
Step-by-step explanation:
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Step-by-step explanation:
Let the number of general tickets = g.
Let the number of reserved tickets = r.
6.5g + 8r = 3284
g + r = 436
6.5g + 8r = 3284
(+) -8g + -8r = -3488
--------------------------------
-1.5g = -204
g = 136
g + r = 436
136 + r = 436
r = 300
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Answer:
Equation: r-20=74
Step-by-step explanation:
So he started with 94. I got B
So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.
Now plug in the value of θ for cosine:
cos (2π/3) = -1/2
And tangent:
tan (2π/3) = -√3/3