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Paraphin [41]
2 years ago
13

There were 20 boys and 26 girls in a chess club last year. This year the number of boys increased by 30% but the number of girls

decreased by 15%. Was there an increase or
decrease in overall membership?
Mathematics
1 answer:
Readme [11.4K]2 years ago
5 0

Step-by-step explanation:

Boys

20 + (20 \div 100)30 = \\  = 20 + 0.2 \times 30  =   \\  = 20 + 6 = \\26

Girls

26 - (26 \div 100)15 = \\  = 26 - 0.26 \times 15 =  \\  = 26 - 3.9 = \\  = 22

Total last year 46

Total this year 48

Increase

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Please help me with this
horrorfan [7]

Answer:

\dfrac{4000\pi}{3} ft³

Step-by-step explanation:

First, let's figure out how to get the <em>volume </em>of a sphere from its <em>surface area</em>. If r is the radius of our sphere, then

The formula for a sphere's surface area is A = 4\pi r^2

The formula for a sphere's volume is V=\frac{4}{3}\pi r^3

So to get from area to volume, we have to <em>divide the area by 3 </em>and then <em>multiply it by r.</em> Mathematically:

V=\frac{A}{3}r

Before we solve for V though, we need to find the radius of our sphere. Thankfully, we're given the surface area - 400\pi ft² - so we can use the area formula to find that radius:

A=4\pi r^2=400\pi\\r^2=100\\r=10

And now that we have our radius, we can put it into our volume formula to find

V=\frac{A}{3} r=\frac{400\pi}{3}(10)=\frac{4000\pi}{3} ft³

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Do the following form a right triangle?<br> 20, 25, 30<br> True<br> False
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Read 2 more answers
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\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

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