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3 years ago

12 3/5 x 30 = tyyyyyy

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Answer:

378 is the answers it's not hard

Tasya [4]3 years ago

4 0

12 3/5 x 30 = 378

Can I get brainliest?

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Please solve the following sum or difference identity.

xxTIMURxx [149]

Answer:

$sin(A - B) = \frac{4}{5}$

Step-by-step explanation:

Given:

$sin(A) = \frac{24}{25}$

$sin(B) = -\frac{4}{5}$

Need:

$sin(A - B)$

First, let's look at the identities:

sum: $sin(A + B) = sinAcosB + cosAsinB$

difference: $sin(A - B) = sinAcosB - cosAsinB$

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = $\frac{24}{25}$

cos(A) = $\frac{7}{25}$

sin(B) = $-\frac{4}{5}$

cos(B) = $\frac{3}{5}$

Plug these values into the difference identity formula.

$sin(A - B) = sinAcosB - cosAsinB$

$sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})$

Multiply.

$sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})$

Add.

$sin(A - B) = \frac{4}{5}$

This is your answer.

Hope this helps!

6 0

3 years ago

Read 2 more answers

A store buys frozen burritos from a supplier for $1.40 each. The store adds a markup of 80% to determine the retail price. This

boyakko [2]

$1.40 - price from a supplier = 100%
100% + 80% = 180% = 1,8 - the retail price

1,40 * 1,8 = $2,52 - the retail price

100% - 25% = 75% = 0,75 - on sale for 25% off

2,52 * 0,75 = $1,89 - the sale price.

8 0

3 years ago

Question 8 of 10

Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

Mean is affected by extreme values
Mean is not correct if more outliers are present
Mean may not represent the nature of the data whether skewed right or left.

Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.