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forsale [732]
3 years ago
8

Find using Pythagorean theorem Find the distance (2, 8) (3, -9)

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

√290

Step-by-step explanation:

( 2 - 3 )^2 + ( 8 + 9 )^2

= ( - 1 )^2 + 17^2

= 1 + 289

= 290

= √290

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What are the exact solutions of x^2 − 3x − 7 = 0?
bulgar [2K]

<u>Given</u>:

The given equation is x^{2} -3x-7=0

We need to determine the exact solutions of the equation.

<u>Exact solution:</u>

The exact solution of the equation can be determined by solving the equation using quadratic formula,

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

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Thus, substituting these values in the equation, we get;

x=\frac{-(-3) \pm \sqrt{3^2-4(1)(-7)}}{2(1)}

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x=\frac{3 \pm \sqrt{37}}{2}

Thus, the exact solutions of the given equation is x=\frac{3 \pm \sqrt{37}}{2}

Hence, Option A is the correct answer.

6 0
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Please Help! Question is:
Natasha_Volkova [10]

Answer: D

Step-by-step explanation:

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A cookie factory monitored the number of broken cookies per pack yesterday.
trapecia [35]

Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given  

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20  

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } } \leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

2.290 < S < 2.965

8 0
3 years ago
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