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tia_tia [17]
3 years ago
15

A construction crew is lengthening a road. The road started with a length of 59 miles, and the crew is adding 4 miles to the roa

d each day. Let L represent the total length of the road (in miles), and let D represent the number of days the crew has worked. Write an equation relating L to D . Then use this equation to find the total length of the road after the crew has worked 31 days.
Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

The total length of the road after the crew has worked 31 days is 183 miles.

Step-by-step explanation:

As given

A construction crew is lengthening a road.

The road started with a length of 59 miles, and the crew is adding 4 miles to the road each day.

let L represent the total length of the road (in miles).

let D represent the number of days the crew has worked.

Than the equation becomes

L = 59 + 4D

Now find out the total length of the road after the crew has worked 31 days.

D = 31 days

Put in the equation

L = 59 + 4 × 31

  = 59 + 124

L  = 183 miles

Therefore the total length of the road after the crew has worked 31 days is 183 miles.



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2 years ago
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3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
Simplify (5x2 + x – 11) – (3x² + 4x – 17)
tatiyna

Answer:

2 x^2 - 3 x + 6

Step-by-step explanation:

Simplify the following:

-(3 x^2 + 4 x - 17) + 5 x^2 + x - 11

-(3 x^2 + 4 x - 17) = -3 x^2 - 4 x + 17:

-3 x^2 - 4 x + 17 + 5 x^2 + x - 11

Grouping like terms, 5 x^2 - 3 x^2 + x - 4 x - 11 + 17 = (5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17):

(5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17)

5 x^2 - 3 x^2 = 2 x^2:

2 x^2 + (x - 4 x) + (-11 + 17)

x - 4 x = -3 x:

2 x^2 + -3 x + (-11 + 17)

17 - 11 = 6:

Answer: 2 x^2 - 3 x + 6

3 0
3 years ago
Read 2 more answers
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GREYUIT [131]

Answer:

83

Step-by-step explanation:

6 0
3 years ago
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