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kirill [66]
3 years ago
5

A swimming pool is in the shape of a right rectangular prism. If the pool is 9 ½ yards long, 7 ⅖ yards wide, and 8 yards deep, w

hat is the volume of the swimming pool?
Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

3 yards long and 2 4/5 yards wide and 1 2/5 yards tall

Step-by-step explanation:

Sholpan [36]3 years ago
4 0
The answer is: 562.4
The volume of a rectangle can be found by doing length*width*height
Or
9.5*7.4*8 which equals 562.4
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Find the second derivative y= x^2lnx
Dimas [21]
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
         1+2+2lnx
         3+2lnx is the answer


3 0
3 years ago
NEED HELP IN FINDING AREA
Aliun [14]

Answer:

809 km²

Step-by-step explanation:

I can split this into 3 rectangles. One is 25 by 17, another is 24 by 13, and the last one is 6 by 12. (I had gotten 13 for the second rectangle because 25 - 12 = 13.)

(25 * 17) + (24 * 13) + (6 * 12) <em>{17 is the first number after a multiple of 4 (16). As a result, 25 by 17 will end in "25." 25 by 17 is 425.}</em>

425 + (24 * 13) + (6 * 12) <em>{24 by 13 is 312.}</em>

425 + 312 + (6 * 12) <em>{6 by 12 is 72.}</em>

425 + 312 + 72 <em>{From left to right, add 425, 312, and 72 to get 809}</em>

737 + 72

809 km²

The area of this figure is 809 km².

5 0
3 years ago
The area of a circular field is 16π square miles. What is the diameter of the field in miles.
ella [17]

Answer:

8

Step-by-step explanation:

1. Divide the area (in square units) by Pi (approximately 3.14159).

2. Take the square root of the result. This is the radius.

3. Now double the radius to get the diameter

3 0
3 years ago
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3 years ago
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In ΔUVW, the measure of ∠W=90°, VW = 32 feet, and WU = 78 feet. Find the measure of ∠V to the nearest degree.
DanielleElmas [232]

Answer: 67.68^{\circ}

Step-by-step explanation:

Given

\angle W=90^{\circ}

VW=32\ ft

WU=78\ ft

from the figure, we can write

\Rightarrow \tan v=\dfrac{UW}{VW}\\\\\Rightarrow \tan v=\dfrac{78}{32}\\\\\Rightarrow \tan v=2.437\\\Rightarrow v=\tan^-1(2.437)\\\Rightarrow v=67.68^{\circ}

7 0
3 years ago
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