Answer:
3.1 ns ; 1.25 ; 3.097
Explanation:
Given :
IF, 3 ns;
ID, 2.5 ns;
EX, 2 ns;
MEM, 3 ns;
WB, 1.5 ns.
Use 0.1 ns for the pipelineregisterdelay
maximum time required for MEM = 3 ns
Pipeline register delay = 0.1 ns.
Clock cycled time of the pipelined machine= maximum time required + delay
3ns+0.1 ns = 3.1 ns
2.) for stall after every 4 instruction :
CPI of new machine :
(1 + (1 /4)) = 1 + 0.25 = 1.25
3.)
The speedup of pipelined machine over the single-cycle machine is given by :
Average time per instruction of single cycle ÷ average time per instruction of pipelined
Clock time of original machine = 12ns
Ideal CP1 = 1
CPI of new machine = 1.25
Clock period = 3.1 ns
(12 * 1) / (1.25 * 3.1) = 12 / 3.875
= 3.097
D. Speed up will equal the number of stages in the machine
Answer: B and E
Responsive display ads and uploaded image ads
Explanation:
A responsive display ad is an advert that can automatically adjust its size and format to suits any available ad space. Responsive display ads are the default ad type for the Google Display Network.
While the uploaded image ads AMPHTML (Accelerated Mobile Pages) is just perfect for mobile devices as it loads faster than other type of ads.
Answer:
1. the set of real numbers between 0.1 and 0.2
2. the set of all negative integers greater than negative 1 trillion
3. the set of all java and C programs
Explanation:
A set is countable if it is either finite or has the same cardinality as the set of positive integers. The inverse of this set type is uncountable.
The set of real numbers between 0.1 and 0.2, all negative integers greater than negative 1 billion, and a set of java and C programs are all countable sets, so are considered countably infinite.
Answer:
Check the explanation
Explanation:
10
5
3
21
2
-6
the output will be somthing like this:
2 21
You can then suppose that the list of integers will contain at least 2 values.