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tino4ka555 [31]
3 years ago
9

3. Write a method squareOfAsterisks that displays a solid square (the same number of rows and columns) of asterisks whose side i

s specified in integer parameter side. For example, if side is 4, the method should display **** **** **** **** Incorporate this method into an application that reads an integer value for side from the user and outputs the asterisks with the squareOfAsterisks method.
Computers and Technology
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

Following are the program to this question:

#include <iostream>//defining header file

using namespace std;

void squareOfAsterisks(int x) //defining method squareOfAsterisks

{

   int i,j; //defining integer variable

   for(i=1;i<=x;i++) //defining loop to print column value

   {

   for(j=1;j<=x;j++) //defining loop to print row value

   {

   cout<<"*"; //print value

   }

   cout<<endl; //for line break

   }

}

int main() //defining main method

{

int x; //defining integer variable

cout<<"Enter any number: "; //print message

cin>>x; //input value from user

squareOfAsterisks(x); //calling the method and pass the value

return 0;

}

Output:

Enter any number: 4

****

****

****

****

Explanation:

The description of the above program can be given as follows:

  • In the given program a method "squareOfAsterisks" is declared, that accepts an integer value "x" in its arguments, inside the method two integer variable I, j is used, that uses a to print the given pattern.
  • In the main method, an integer variable x is declared, which takes input from the user end, and then calls the method, that is "squareOfAsterisks" and passes its value.
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class llist { private: record * start; char filename[16]; int readfile(); int writefile(); record * reverse(record * ); void cle
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Answer:

See Explaination

Explanation:

#include <cstdlib>

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

#include <sstream>

using namespace std;

struct Person

{

string name;

string addr;

string phone;

string id;

};

const int MAX_SIZE = 8;

void addData(Person list[], int& size);

void dispData(const Person list[], int size);

void delData (const Person list[], int size);

void saveFile(const Person list[], int size);

void openFile(Person list[], int& size);

char getMenuResponse();

int main(int argc, char *argv[])

{

Person contactList[MAX_SIZE];

int numOfRecs = 0;

bool run = true;

do

{

cout << "Address Book - " << numOfRecs << " Number of Contacts" << endl;

switch ( getMenuResponse() )

{

case 'A': addData(contactList, numOfRecs); break;

case 'D': dispData(contactList, numOfRecs); break;

case 'T': delData(contactList, numOfRecs); break;

case 'O': openFile(contactList, numOfRecs); break;

case 'S': saveFile(contactList, numOfRecs); break;

case 'Q': run = false; break;

default : cout << "That is NOT a valid choice" << endl;

}

} while (run);

cout << endl << "Program Terminated" << endl;

return EXIT_SUCCESS;

}

void addData(Person list[], int& size)

{

Person tmp;

char response;

char str[256];

if (size < MAX_SIZE) {

system("cls");

cout << "Enter Contact Information" << endl << endl;

cout << "Name: ";

cin.getline(str, 256, '\n');

tmp.name = str;

cout << endl;

cout << "Address: ";

cin.getline(str, 256, '\n');

tmp.addr = str;

cout << endl;

cout << "Phone Number: ";

cin.getline(str, 256, '\n');

tmp.phone = str;

cout << endl;

cout << "E-mail id Address: ";

cin.getline(str, 256, '\n');

tmp.id = str;

cout << endl;

cout << "Add Contact to Address Book? (y/n) ";

cin >> response;

if (toupper(response) == 'Y')

list[size++] = tmp;

} else {

cout << "Sorry, Address Book is currently full." << endl;

system("pause");

}

system("cls");

}

void dispData(const Person list[], int size)

{

system("cls");

if(size < 1)

{

cout << "Nothing to display" << endl;

} else {

cout << "Contacts :" << endl << endl;

cout << fixed << setprecision(2);

cout << "Contact Name Address Phone No. ID" << endl;

cout << left;

for (int i = 0; i < size; i++)

{

cout << setw(10) << list[i].name << right

<< setw(10) << list[i].addr<<right

<< setw(10) << list[i].phone<<left

<< setw(15) << list[i].id<<left<<endl;

}

cout << right << setw(3) << size;

cout << " Contacts"<< endl;

}

system("PAUSE");

system("cls");

}

void delData(const Person list[],int size) {

vector<Person> :: iterator vItr = Contact.begin();

while (vItr != Contact.end() )

{

if (vItr->Name == Name)

{

vItr = Contact.erase (vItr);

break;

}

else

vItr++;

}

void saveFile(const Person list[], int size) {

string fileName;

ofstream outfi;

cout<<"Enter file name: ";

getline(cin,fileName);

outfi.open(fileName.c_str());

if (!outfi.fail()) {

system("cls");

cout << "Saving Address Book to the disc ";

for(int i = 0; i < size; i++) {

outfi << list[i].name << ';'

<< list[i].addr<< ';';

if (i < size-1) outfi << endl;

}

cout << endl << size << " Address Book in the disc." << endl;

outfi.close();

system("PAUSE");

system("cls");

}

else {

cout << "ERROR: problem with file" << endl;

system("PAUSE");

system("cls");

}

}

void openFile(Person list[], int& size)

{

ifstream infi("AddressBook.txt");

string str;

stringstream strstrm;

if (!infi.fail()) {

system("cls");

cout << "Reading Address Book from the disc ";

size = 0;

while(!infi.eof() && size < MAX_SIZE)

{

getline(infi, str, ';');

list[size].name = str;

getline(infi, str, ';');

strstrm.str(""); strstrm.clear();

strstrm << str;

strstrm >> list[size].addr;

}

cout << endl << size << " read contacts from the disc." << endl;

system("PAUSE");

system("cls");

}

else {

cout << "ERROR :file not accepted" << endl;

system("PAUSE");

system("cls");

}

}

char getMenuResponse()

{

char response;

cout << endl << "take chioce" << endl

<< "(A)dd contact, (D)isplay contact0, (O)pen File, (S)ave File, (Q)uit" << endl

<< "> ";

cin >> response;

cin.ignore(256, '\n');

return toupper(response);

}

8 0
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Pendant Publishing edits multi-volume manuscripts for many authors. For each volume, they want a label that contains the author’
tigry1 [53]

Answer:

The answer to this question can be described as follows:

Explanation:

The Pseudocode to this question can be described as follows:

start  \\ start process

Declaration of variable

Input_File records.txt

Output_File result.txt

string author_Name , title

int number_of_volume

open Input_File

open Output_File

input author_Name, title, number_of_volume from records.txt

while not eof \\ start loop and eof is end of file  

output author_Name

output title

output number_of_volume

end while  \\end loop

close records.txt  \\close file

close results.txt   \\close file

END \\end the code

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Suppose x is 1. What is x after x = 1?<br> A. -1<br> B. 0<br> C. 1<br> D. 2<br> E. -2
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Answer:

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Explanation:

also 339399393993939399393

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