Answer:
Check the explanation
Explanation:
Answer: Solution: Algorithm:
Step 1: Start.
Step 2: Create a stack Step
3: Push an initial stack variable, it will represent that, stack is empty.
Step 4: Get input
If +1 then push "+1"
Else if -1 then pop
Step 5: Repeat until all input finish or Stop if empty stack variable popped. Step 6: Stop.
It is a pushdown automata problem.
It can be also represented as:
X =1+1* —1* 1No(+1)>= No(-1)}
Answer:
Explanation:
The following code is written in Java. The function takes in the random object and creates a random number where it generates a random number and prints out the * characters, if the random number and the input num are the same it prints out both values and ends the function.
import java.util.Random;
class Brainly {
public static void main(String[] args) {
Random r = new Random();
randomStar(r, 12);
System.out.println();
randomStar(r, 19);
}
public static void randomStar(Random r, int num) {
while (true) {
int randomNum = r.nextInt(19) + 5;
if (randomNum != num) {
for (int x = 0; x < randomNum; x++) {
System.out.print("*");
}
System.out.print("\n");
} else {
for (int x = 0; x < randomNum; x++) {
System.out.print("*");
}
System.out.print("\n");
System.out.println("Random Number: " + randomNum);
System.out.println("Input Number: " + num);
break;
}
}
}
}
Go to the me colum when you first open the app
Answer:
The result is -63
Explanation:
First, we discover the Binary value of 151 which is 10010111.
1 = most significant bit and it represents the sign as negative.
Two's compliment of 10010111, is calculated by adding 1 to one's compliment. We get 01101001 which is 105 in decimal.
Therefore the value of A (the first part) is -105.
Second, the binary value of 214 = 11010110.
1 = most significant bit and it represents the sign as negative.
Two's compliment of 11010110, is calculated by adding 1 to one's compliment. We get 00101010 which is 42 in decimal.
Therefore, the value of B (the second part) is -42.
Simplify further,
A - B = -105 - (-42)
= -105 + 42
= -63
Therefore, the result is -63,
To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane.
<h3>How is boundary layer thickness calculated?</h3>
- Where x is a position parallel to the wall, y is a coordinate normal to the wall, v is a (small) viscosity, u = (u, v) is the velocity, is the vorticity, and so on. The boundary conditions are as follows: u(x,y = +,t) = U, and u(x,y = 0,t) = 0.
- To gauge the overall pressure, a vertically sliding Pitot tube is employed. So that the growth of the boundary layer in the flow direction can be seen, the total pressures can be recorded at various distances from the plate surface. Static pressure is gauged at a different measurement location.
- To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane. Alternatively, you can pick a discrepancy and choose Replace Content from the Comparison tab.
To learn more about Boundary conditions refer to:
brainly.com/question/23802083
#SPJ4
