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The table shows the distance the students a group of students walked during after-school practice. What was the total distance,

ser-zykov [4K]

First let's convert the decimal numbers to mixed numbers:

$\begin{gathered} 3.4=3+0.4=3+\frac{4}{10}=3+\frac{2}{5}=3\frac{2}{5} \\ 1.75=1+0.75=1+\frac{75}{100}=1+\frac{3}{4}=1\frac{3}{4} \\ 2.25=2+0.25=2+\frac{25}{100}=2+\frac{1}{4}=2\frac{1}{4} \end{gathered}$

Now, adding all the numbers, we have:

$\begin{gathered} (3+\frac{2}{5})+(3+\frac{1}{5})+(1+\frac{3}{4})+(2+\frac{1}{4})+(1+\frac{7}{10}) \\ =(3+3+1+2+1)+(\frac{2}{5}+\frac{1}{5}+\frac{3}{4}+\frac{1}{4}+\frac{7}{10}) \\ =10+(\frac{3}{5}+1+\frac{7}{10}) \\ =11+(\frac{6}{10}+\frac{7}{10}) \\ =11+\frac{13}{10} \\ =12+\frac{3}{10}=12\frac{3}{10} \end{gathered}$

So the correct option is B.

8 0

1 year ago

What are rational and irrational numbers Pls Help Asap my homework need to submit very soon

just olya [345]

Answer:

Rational numbers are the numbers that can be expressed in the form of a ratio (P/Q & Q≠0) and irrational numbers cannot be expressed as a fraction

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The radius of a circle is 7 kilometers. What is the length of a 90° arc?

LUCKY_DIMON [66]

Find the length of the circumference:

Circumference = 2 x pi x radius

Circumference = 2 x 3.14 x 7

Circumference = 43.96 kilometers

90 degrees is 1/4 of a circle ( 360/4 = 90)

Arc length = 43.96/4 = 10.99 kilometers

(Round answer as needed)

4 0

3 years ago

The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 2.4 cars and a

liberstina [14]

Answer:

The sampling distribution of the sample mean is:

$\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)$

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Let X = number of cars running a red light in a day, at a given intersection.

The information provided is:

$E(X)=\mu=2.4\\SD(X)=\sigma=4\\n=100$

The sample selected is quite large, i.e. n = 100 > 30.

The Central limit theorem can be used to approximate the sampling distribution of the sample mean number of cars running a red light in a day, by the Normal distribution.

The mean of the sampling distribution of the sample mean is:

$\mu_{\bar x}=\mu=2.4$