Answer:
The correct answer is - B) Elysia Chlorotica grows when exposed to light in the absence of other food sources
Explanation:
If placing Elysia Chlorotica in presence of the food sources in the presence or absence of light it still grows as normal. However, if placing in the light in absence of the food sources it should not grow if it is not able to perform photosynthesis but it does which means there is a photosynthesis process also involve in the Elysia.
Photosynthesis is the process that involves the production of energy and nutrition in presence of light with water and atmospheric carbon dioxide.
When focusing on a slide, ALWAYS start with either the 4X or 10X objective. Once you have the object in focus, then switch to the next higher power objective.
Liters because liters are larger than milliliters.
Answer:
They could have all four type phenotype that are A, B, AB, and O
Explanation:
If the man has A blood group and the woman has B blood group then the genotype of man can be IAIA or IAi and the genotype of woman can be IBIB or IBi.
IA i
IB IAIB IBi
i IAi ii
So if the genotype of the parents are IAi and IBi then out of four offspring one could have AB blood group, second could have B blood group, third could have A blood group and fourth could have O blood group as shown in the cross above.
Answer: Codominance
Explanation:
Since neither type A blood nor type B is dominant over the other (i.e both are codominant), the offspring of both parents will be with type AB blood.
Thus, codominance explains how the two alleles are present in the Heterozygous individual IAIB, showing they are both fully expressed.
