Help!!!! 20 points!!!!!!’

Mathematics

1 answer:

Gnoma [55]2 years ago

3 0

Answer:

option c is the correct answer

first take y raised to the power 4 common then cancel its power by y raised to the power 3

you get your answer

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Hii please answer really easy xx

dlinn [17]

Answer:

Step-by-step explanation:

find only for x or?

8 0

3 years ago

Solve for k. m=−8j−9k+9

inn [45]

Answer: k = -8/9j + -1/9m + 1

Step 1: Flip the equation.−8j − 9k + 9 = m

Step 2: Add -9 to both sides.−8j − 9k + 9 + −9 = m + −9−8j − 9k = m − 9

Step 3: Add 8j to both sides.−8j −9k + 8j = m −9 + 8j−9k = 8j + m −9

Step 4: Divide both sides by -9.
-9k/-9 = 8j + m - 9/-9
k = -8/9j + -1/9m + 1

7 0

2 years ago

Read 2 more answers

NEED ANSWER ASAP REALLY IMPORTANT i will take any of the answers

dedylja [7]

$1. \: MC \: is \: tangent \: to \: (B)\Rightarrow \widehat{BCM}=90° \\ 2. \: MC \: and \: MZ \: are \: tangent \: to \: (B)\Rightarrow MC = MZ\Leftrightarrow 5x - 9 = x + 7\Leftrightarrow x = 4 \\ 3. \: BM = \sqrt{ {BC}^{2} + {MC}^{2} } = \sqrt{ {5}^{2} + {12}^{2} } = 13 \\ \Rightarrow EM = BM - BE = BM - BC = 13 - 5 = 8 \\ 4. \: \tan(60°) = \frac{MC}{BC} = \frac{13 \sqrt{3} }{ BC}\Leftrightarrow BC = \frac{13 \sqrt{3} }{\tan(60°)} = \frac{13 \sqrt{3} }{ \sqrt{3} } = 13 \\ 5. \: MC = \sqrt{ {BM}^{2} - {BC}^{2} } = \sqrt{ {20}^{2} - {12}^{2} } = 16 \\ 6. \:BZ = \sqrt{ {BM}^{2} - {MZ}^{2} } = \sqrt{ {25}^{2} - {20}^{2} } = 15 \\ \Rightarrow XE=BX+BE=BZ+BZ=15+15=30$