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Dominik [7]
2 years ago
10

9. Felix has a bucket of golf balls. The table shows the number of golf balls of each color in the bucket. Felix selects a golf

ball at random. Based on the information in the table, which statement is true? * PLEASE HELP ME IM CONFUZZELD​

Mathematics
1 answer:
mestny [16]2 years ago
4 0

Answer:

The golf ball is 2 times a likely to be orange as it is to be pink

Step-by-step explanation:

A. green = 18, pink+white+orange = 23

    18 not > 23

B. pink \neq white \neq orange \neq green

C. pink x 2 = orange?

    4 x 2 = 8

D. white x 7 = green?

    white = 11

     green = 18

   11 x 7 = 77 \neq 18

 

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That is the one my friend and I chose. It is 31/61 when all the stuff is added together and that is put to 50.8 as a percentage..

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Express 0.032 as a fraction in lowest terms
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A reflection is a transformation that maps point Q in a figure over a line, AB, such that for point C at th intersection of AB a
Goshia [24]

Answer: \overline{QC}\cong\overline{Q'C'} and \angle{ACQ} is a right angle .


Step-by-step explanation:

Given : A reflection is a transformation that maps point Q in a figure over a line, AB, such that for point C at the intersection of AB and QQ'.

We know that reflection creates a image equidistant from the line of reflection.

Thus,  \overline{QC}\cong\overline{Q'C'}

Also in reflection , a line drawn from the point is perpendicular to the line of reflection.

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5 0
3 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
3 years ago
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