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ZanzabumX [31]
3 years ago
12

Find the y intercept of the line 3 x − 2 y = 16

Mathematics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

y-intercept = (0,-8)

Step-by-step explanation:

To find the y-intercept, substitute in  0  for  x  and solve for y.

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◕ A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer. The retailer added transportation cost of Rs 250 , pr
satela [25.4K]

<u>Given </u><u>:</u><u>-</u>

  • A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer.
  • The retailer added transportation cost of Rs 250 , profit Rs 300 and local tax Rs 150 and sold to consumer .
  • Customer has to pay 13% VAT .

<u>To </u><u>Find </u><u>:</u><u>-</u>

  • Amount to be paid by the customer .

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u>

Here , according to the question ,

\sf\dashrightarrow Cost\ of \ machine \ = \ Rs 4200

\sf\dashrightarrow VAT = 13\%

Therefore cost after adding VAT ,

\sf\dashrightarrow Cost = Cost_{initial}+13\% of Cost_{initial}\\

\sf\dashrightarrow Cost = Rs4200 + Rs 4200 \times \dfrac{13}{100}\\

\sf\dashrightarrow Cost = Rs4200 + Rs546\\

\sf\dashrightarrow \bf{ Cost = Rs 4746}

Again the values added by the retailer before selling to customer ,

  • Transport = Rs 250
  • Profit = Rs 300
  • Tax = Rs 150

Therefore total cost after adding these ,

\sf\dashrightarrow Cost = Rs( 4746+ 250+ 300 + 150 )\\

\sf\dashrightarrow\bf { Cost = Rs 5446}

Again Selling price after addition of 13% VAT ,

\sf\dashrightarrow SP = Rs 5446 + 13\% \ of \ Rs 5446\\

\sf\dashrightarrow SP = Rs 5446 + \dfrac{13}{100}\times 5446 \\

\sf\dashrightarrow SP = Rs (5446 + 707.98) =  Rs ( 5446 + 708)\\

\sf\dashrightarrow \underline{\underline{\bf SP_{to\ the \ customer} = Rs 6154}}

<u>Hence </u><u>the </u><u>amount </u><u>to </u><u>be </u><u>paid </u><u>by </u><u>the </u><u>customer </u><u>is </u><u>Rs </u><u>6</u><u>1</u><u>5</u><u>4</u><u> </u><u>.</u>

3 0
2 years ago
Read 2 more answers
Which Expression is equivalent to 48z +42q<br><br> A) 6(8z+7q)<br><br> B) 6*8z+7q<br><br> C) 8z+7q
Butoxors [25]

Answer:

6(8z+7q)

Step-by-step explanation:

48z+42q

Factor out 6.

6(8z+7q)

5 0
3 years ago
The area of a triangle is 36 4/5 units squared and the height of the triangle 9 1/5 what is the length of the triangles base
den301095 [7]

Answer:

Height = 8 units

Step-by-step explanation:

Area of a triangle = 36\frac{4}{5} square units

                             = \frac{184}{5} square units

Height of the triangle = 9\frac{1}{5} units

                                    = \frac{46}{5} units

Formula to calculate the area of a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

\frac{184}{5}= \frac{1}{2}\times (\frac{46}{5})\times (\text{Height})

\frac{184}{5}= (\frac{46}{10})\times (\text{Height})

Height = \frac{184}{5}\times \frac{10}{46}

           = \frac{368}{46}

           = 8 units

Therefore, height of the given triangle is 8 units.

6 0
3 years ago
Read 2 more answers
Which expression has twice the value of 2•2•2•2•2? <br> A. 2^6 <br> B. 2^10 <br> C. 4^5<br> D. 4^10
IgorC [24]
2x2x2x2x2=32

32x2=64

2x2x2x2x2x2=64

2^6 is your answer
3 0
3 years ago
Read 2 more answers
Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account
Diano4ka-milaya [45]

Answer:

\$180.55

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04

substitute in the formula above

A=2,250(1+0.04*10)

A=2,250(1.4)

A=\$3,150

step 2

<u><em>Interest compounded annually</em></u>

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1

substitute in the formula above

A=2,250(1+\frac{0.04}{1})^{1*10}  

A=2,250(1.04)^{10}  

A=\$3,330.55

step 3

Find the differences between the two final amounts

A=\$3,330.55-\$3,150=\$180.55

5 0
3 years ago
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