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slava [35]
3 years ago
14

Two sides of an isosceles triangle have lengths of 4 and 8. What is the length of the third side?

Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

Answer:

8

Step-by-step explanation:

Let's start with a simple fact: two sides of an isosceles triangle must be equal. Let's suppose the missing side is 4

That would mean that 4 + 4 equals 8. You must pick a side that exceeds 8, but you loose the property of 2 sides need to be equal.

So the answer has to be 8. The final size of the sides is 4 8 and 8. 4 and 8 exceed the third side (8).

8 and 8 certainly exceed 4.

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15. -2 (a - 4) = 13​
iogann1982 [59]

Answer:

a=-22

Step-by-step explanation:

Multiply both sides of the negative equation by (-2) to get the equation:

a-4=13(-2)

then simplify to get:

a-4=-26

then isolate the variable by addig 4 to both sides of the equation to get:

a=-26+4

simplify to get:

a=-22

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2 years ago
Ross needs to have a procedure done, and since he is over 65 he is on Medicare. Medicare says that according to their plan the a
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Answer:

\large \boxed{\$1200.00}

Step-by-step explanation:

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Solve for x

\begin{array}{rcrl}\dfrac{1}{4} \left(\dfrac{7}{8}x \right ) & = & \$262.50 & \\\dfrac{7}{32}x & = & \$262.50 & \text{Multiplied the fractions}\\\\7x & = & \$8400.00 & \text{Multiplied each side by 32}\\x & = & \mathbf{\$1200.00} & \text{Divided each side by 7}\\\end{array}\\\text{The office wanted to charge } \large \boxed{\mathbf{\$1200.00}}

Check:

\begin{array}{rcl}\dfrac{1}{4} \left(\dfrac{7}{8}\times \$1200.00 \right ) & = & \$262.50\\\\\dfrac{1}{4} \left(\$1050.00 \right ) & = & \$262.50\\\\\$262.50 & = & \$262.50\\\end{array}

OK.

7 0
3 years ago
How do I solve the equation? -34= v+42-5v
Alex17521 [72]
-34=v+42-5v
-76=-4v
V= 19
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