Two sides of an isosceles triangle have lengths of 4 and 8. What is the length of the third side?

Mathematics

1 answer:

Gnoma [55]3 years ago

3 0

Answer:

Step-by-step explanation:

Let's start with a simple fact: two sides of an isosceles triangle must be equal. Let's suppose the missing side is 4

That would mean that 4 + 4 equals 8. You must pick a side that exceeds 8, but you loose the property of 2 sides need to be equal.

So the answer has to be 8. The final size of the sides is 4 8 and 8. 4 and 8 exceed the third side (8).

8 and 8 certainly exceed 4.

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How do I do this? (3x^2+8)-(2x^2+1) So first I add like terms? 5x^2 + 8 + 1

Gemiola [76]

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= 3x² + 8 - 2x² - 1
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3 years ago

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hram777 [196]

Answer:

On a coordinate plane, a line goes through (0, 3) and (2, 4) and another line goes through (0, 3) and (0.75, 0).

This answer almost coincide with option C. I suppose there was a mistype.

Step-by-step explanation:

The system of equations is formed by:

–x + 2y = 6

4x + y = 3

In the picture attached, the solution set is shown.

The first equation goes through (0, 3) and (2, 4), as can be checked by:

–(0) + 2(3) = 6

–(2) + 2(4) = 6

The second goes through (0, 3) and (0.75, 0), as can be checked by:

4(0) + (3) = 3

4(0.75) + (0) = 3

7 0

3 years ago

Read 2 more answers

Round to the nearest hundredth if so. Use 3.14 as pi 8. r= d = C=78.8 ft

Kryger [21]

Answer: The radius is 12.54 feet, and the diameter is 25.08 feet.

Explanation: By applying the circumference into the equation r = $\frac{C}{2\pi }$ , we get r = $\frac{78.8}{2\pi }$ which simplifies the radius. And since radius is half of diameter, we multiply by 2 to get the diameter as well to solve the other blank in the problem.