1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Assoli18 [71]
3 years ago
10

What is the surface area of this triangular prism

Mathematics
1 answer:
const2013 [10]3 years ago
6 0
The perimeter of the triangular end is 12 m, so the total rectangular area is
.. (12 m)*(8 m) = 96 m^2

There are two triangles with base 3 m and height 4 m, so their total area is
.. (3 m)*(4 m) = 12 m^2

The surface area of the figure is the sum of these 
.. 96 m^2 +12 m^2 = 108 m^2
You might be interested in
Write the equation of the line, given the y and x-intercepts:
kolezko [41]

Answer:

The answer to your question is:                161x + 17y - 391 = 0

Step-by-step explanation:

Data

y-intercept = 23         Get the points      (0, 23)

x- intercept = 4.75                                   (4.75, 0)

                      4.75 = 17/4                         (17/4, 0)

slope

              m = (y2 - y1) / (x2 - x1)

              m = (0 - 23) / (17/4 - 0)

              m = -23 / 17/4

             m = - 161 / 17

equation

              (y - y1) = m (x - x1)

              ( y - 23) = -161 / 17 (x - 0)

               y - 23 = -161/17 x

              17(y - 23) = -161x

              17y - 391 = -161x

              161x + 17y - 391 = 0

7 0
3 years ago
Please help me get the answer i’ll give you a thanks and 10 points pls
vitfil [10]
586 cm squared i believe
7 0
3 years ago
Read 2 more answers
What kind of quadrilaterals is this?
DanielleElmas [232]

Answer:

Trapezoid

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can anyone help with the answers to all these questions with an explanation please?
saveliy_v [14]

ANSWER:

1) 25.70 cm 2) 30.84 cm 3) 10.71 km 4) 1.07 km 5) 6.71 cm 6) 10.07  mm

EXPLANATION:

<em>1. Know that the circumference formula for a full circle is:</em>

C = 2\pi r

The value of pi (\pi) = 3.14

The radius (r) will be given in the diagrams.

<em>2. Now we can figure out the perimeters. </em>

<u>Shape One: Semi-circle</u>

C = 2 x 3.14 x 5

C = 31.4 cm

Divide the circumference by 2 because it is a semi-circle. Then add 10 cm to this (because the flat side is 10 cm).

P = \frac{31.4}{2} +10

P = 25.7 cm ≈ 25.70 cm

<u>Shape Two: Semi-circle</u>

C = 2 x 3.14 x 6 (the picture shows the diameter so we need to half that to get the radius)

C = 37.68 cm

Divide the circumference by 2 because it is a semi-circle. Then add 12 cm to this (because the flat side is 12 cm).

P = \frac{37.68}{2}+12

P = 30.84 cm

<u>Shape Three: Quadrant</u>

C = 2 x 3.14 x 3

C = 18.84 km

Divide the circumference by 4 because it is a quadrant. Then add 6 km to this (because the two flat sides are 3 km each and so it is 6 km total).

P = \frac{18.84}{4} +6

P = 10.71 km

<u>Shape Four: Quadrant</u>

C = 2 x 3.14 x 0.3

C = 1.884 km

Divide the circumference by 4 because it is a quadrant. Then add 0.6 to this (because the two flat sides are 0.3 km each and so it is 0.6 km total).

P = \frac{1.884}{4} + 0.6

P = 1.071 km ≈ 1.07 km

<u>Shape Five</u>

C = 2 x 3.14 x 1

C = 6.28 cm

For this shape, we need to subtract the circumference of the missing sector from the circumference of the full circle to obtain the circumference for this shape. So, the circumference for the shape would be:

C =  6.28 - \frac{6.28}{4}

C = 6.28 - 1.57

C = 4.71 cm

Then add the flat sides (1 cm + 1 cm = 2 cm) to this circumference to get the perimeter.

P = 4.71 + 2

P = 6.71 cm

<u>Shape Six</u>

C = 2 x 3.14 x 1.5 (Divide the 3 mm diameter by 2 to get the radius)

C = 9.42 cm

Do the same thing you did for Shape 5.

C = 9.42 - \frac{9.42}{4}

C = 7.065 mm

Then add the flat sides (1.5 + 1.5 = 3) to this circumference.

P = 7.065 + 3

P = 10.065 mm ≈ 10.07 mm

7 0
3 years ago
I need help . This problem is confusing me.<br><br>​
Sholpan [36]

Answer:

The answer is 3093.

3093 (if that series you posted actually does stop at 1875; there were no dots after, right?)

Step-by-step explanation:

We have a finite series.

We know the first term is 48.

We know the last term is 1875.

What are the terms in between?

Since the terms of the series form a geometric sequence, all you have to do to get from one term to another is multiply by the common ratio.

The common ratio be found by choosing a term and dividing that term by it's previous term.

So 120/48=5/2 or 2.5.

The first term of the sequence is 48.

The second term of the sequence is 48(2.5)=120.

The third term of the sequence is 48(2.5)(2.5)=300.

The fourth term of the sequence is 48(2.5)(2.5)(2.5)=750.

The fifth term of the sequence is 48(2.5)(2.5)(2.5)(2.5)=1875.

So we are done because 1875 was the last term.

This just becomes a simple addition problem of:

48+120+300+750+1875

168      +   1050  +1875

          1218          +1875

                         3093

6 0
3 years ago
Other questions:
  • The sum of three consecutive odd integers is 75. find the value of all three integers.
    8·2 answers
  • A triangle is drawn on a coordinate plane. Point A is at (2,6), Point B is at (4,10), and Point C is at (8,5). What is the midpo
    5·1 answer
  • What is the value of x? x/4-5=6
    7·2 answers
  • Find the measure of an interior and an exterior angle of a regular 46-gon
    14·1 answer
  • 5x - 2y<br><br> please give an explanation once you’ve figured out the answer
    6·1 answer
  • Can someone help me with this I really don't understand​
    8·2 answers
  • From 7x^2+5xy-3y^2 subtract the sum of 2x^2+3xy-5y^2 and x^2-7xy-4y^2
    6·1 answer
  • If a and b vary directly and a = 6 when b = 4, what will be the value of a when b = 16?
    15·1 answer
  • (2 squared • 3 to the fourth power) cubed
    8·2 answers
  • In conducting a​ goodness-of-fit test, a requirement is that​ ________. Question content area bottom Part 1 A. the expected freq
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!