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Assoli18 [71]
3 years ago
10

What is the surface area of this triangular prism

Mathematics
1 answer:
const2013 [10]3 years ago
6 0
The perimeter of the triangular end is 12 m, so the total rectangular area is
.. (12 m)*(8 m) = 96 m^2

There are two triangles with base 3 m and height 4 m, so their total area is
.. (3 m)*(4 m) = 12 m^2

The surface area of the figure is the sum of these 
.. 96 m^2 +12 m^2 = 108 m^2
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Help please!!!!!!!!!!!!!
kaheart [24]

Answer:

53

Step-by-step explanation:

6x3=18

8-3=5

6+1=7

7x5=35

35+18=53

I hope this helps!

5 0
3 years ago
Which value of x is in the domain of f(t) = squared x - 7
zloy xaker [14]

Given:

The given function is:

f(x)=\sqrt{x-7}

To find:

The value of x that is in the domain.

Solution:

Domain is the set of input values.

We have,

f(x)=\sqrt{x-7}

We know that the square root is defined for non negative values. So,

x-7\geq 0

x\geq 0+7

x\geq 7

Thus, the domain of the given function is all real number that are greater than or equal to 7.

In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So, x=8 is in the domain of the given function.

Therefore, the correct option is A.

8 0
2 years ago
Factor the expression.<br> = 28x– 14
Veseljchak [2.6K]

Answer:

14(2×-1) is the factorization of this expression

5 0
2 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
How do I begin this equation
alex41 [277]
Trigonometry:
We know that   csc x = 1 / sin x    and π = 180°;
sin 5π/ 6 = sin 150° = 1/2
csc 2π / 3 = 1 / sin 120° = 1 / √3/2 = 2 / √3
Finally:
4 · 1/2 + 7 · ( 2 / √3 )² = 2 + 7 · 4/3 = 
= 2 + 28/3 = 2 + 9 1/3 =  11  1/3
5 0
3 years ago
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