Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Answer:
x = 4 or x = 0.78
Step-by-step explanation:
9x² – 29x – 28 = 0
2 roots: x = ((-(-29) ± √(-29)² - 4 x 9 x (-28)) / (2 x 9)
= (29 ± √841 + 1008) / 18
= (29 ± 43) /18
x = 72 /18 = 4 or
x = -14 /18 = - 0.78
Answer:
Nickels and dimes?
Step-by-step explanation:
Answer:
21 in.
Step-by-step explanation:
The radius is half of the diameter. The diameter (as shown) is 42 inches. Divide that by two to get 21 in.
Sample space = 17 + 7 + 4 = 28
P(pink) = 7/28
P(orange) = 17/28
P(pink or orange) = P(pink) + P(orange)
P(pink or orange) = 7/28 + 17/28
P(pink or orange) = 24/28
P(pink or orange) = 6/7 or 0.857143 or 85.7%
