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2 years ago

The relationship (3,2)(2,5) (8,5) (3,6) is a function A True B) False

Mathematics

2 answers:

ryzh [129]2 years ago

6 0

Answer:

I would say it's B. false

Mila [183]2 years ago

4 0

Answer:

False

Step-by-step explanation:

Look at the inputs (x-values)

If the inputs are the same, the relationship is Not a function.

Inputs (x-values), cannot share the same output (y-values).

Example:

Inputs Outputs

3 2

2 5

8 5

3 6

In the input there are two 3's which causes this to not be a function.

(Outputs can have the same numbers repeating just not inputs.)

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Vertex form is f(x)=a(x-p)^2 +q. How do i determine a?

slamgirl [31]

Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.

y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).

Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,

-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.

The equation of parabola y4 is y+4 = (1/4)x^2

Or you could elim. the fraction and write the eqn as 4y+16=x^2, or

4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.

8 0

3 years ago

Josiah skateboards from his house to school 3 miles away. It takes home 36 minutes. If Josiah’s speed, in miles per minute, is c

arlik [135]

c constant of proportionality is 12

Step-by-step explanation:

36÷3= 12

5 0

3 years ago

Anybody know the answer?

maksim [4K]

x is 3pi/4 and 7pi/4

Type in correctly

8 0

3 years ago

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval. What

dezoksy [38]

Answer:

29.49% probability that a production time is between 9.7 and 12 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, in which d is greater than c, is given by the following formula.

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval.

This means that $a = 8, b = 15.8$

What is the probability that a production time is between 9.7 and 12 minutes?

$d = 12, c = 9.7$ .

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

$P(9.7 \leq X \leq 12) = \frac{12 - 9.7}{15.8 - 8} = 0.2949$

29.49% probability that a production time is between 9.7 and 12 minutes

5 0

3 years ago

Compute I need help

nataly862011 [7]

$(\sqrt{3}-\sqrt{6}+\sqrt{12}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-2\sqrt{6})\times \frac{\sqrt{6}}{2} \\ ((\sqrt{3}+2\sqrt{3})+(-\sqrt{6}-2\sqrt{6}))\times \frac{\sqrt{6}}{2} \\ (3\sqrt{3}-3\sqrt{6})\times \frac{\sqrt{6}}{2} \\ \frac{(3\sqrt{3}-3\sqrt{6})\sqrt{6}}{2} \\ \frac{3(\sqrt{3}-\sqrt{6})\sqrt{6}}{2}$

7 0

2 years ago