Answer:
See below
Step-by-step explanation:
If a proposed value is outside the confidence interval, it is not a plausible value because the interval never catches it. So B is your best choice.
2x^2 + x + 3=0 has only complex roots.
The determinant is 1-4*2*3 = -23
-23 (or any determinant) is the part under the square root sign, If that determinant is negative, knowing you cannot take the square root of a negative number, we know the answers must be complex.
Answer:
x=−1 or x=−9
Step-by-step explanation:
x2+11x+10=x+1
Step 1: Subtract x+1 from both sides.
x2+11x+10−(x+1)=x+1−(x+1)
x2+10x+9=0
Step 2: Factor left side of equation.
(x+1)(x+9)=0
Step 3: Set factors equal to 0.
x+1=0 or x+9=0
x=−1 or x=−9
Usually, quadratic equations equal 0, and to find the solution you need to make x equal the value that, when added or subtracted to the rest of its bracket, makes 0. This means that your answer is (x + 5)(x - 2) = 0, because 5 - 5 = 0 and 2 - 2 = 0. I hope this helps! Let me know if you would like me to explain further :)
(x-xo)²+(y-yo)²=r²
(x-9)²+(y-3)²=64
r²=64
Area of a circle=πr²=3.14×64=200.96
