Answer:
a)
if 1 quarter = $ 0.25
1 dime = $ 0.10
1 penny = $ 0.01
so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar
therefore we say;
1 Quarter + 8 dimes + 3 penny
: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )
: 0.25 + 0.80 + 0.03 = $ 1.08
b)
Now if you have a 4 Quarters, you have change for $1.
If you have 5 dimes, you have change for 2 Quarters.
If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.
If you have 5 pennies, you have enough change for 1 nickel
Therefore
(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x
(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x
x = 0.75 + 0.4 + 0.04
x = $ 1.19
PROVED
Answer:
I think you would have to draw lines like is the graph book, you will see that they have two axes which is the y and the x.You will then have to fix in numbers and indicate the y= 2x+1.
Step-by-step explanation:
hope it helps
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Answer: c=38.89
b=29.79
<A=40
Explanation:
I hope this helped!
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- Zack Slocum
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Answer: the length is 11 cm.
The width is 7 cm.
Step-by-step explanation:
Let L represent the length of the rectangular plastic box.
Let W represent the width of the rectangular plastic box.
The area of the rectangular top of the box is 77 square cm. This means that
LW = 77- - - - - - - ;- - - -1
The plastic box has a length 4 cm longer than its width. This means that
L = W + 4
Substituting L = W + 4 into equation 1, it becomes
(W + 4)W = 77
W² + 4W = 77
W² + 4W - 77 = 0
W² + 11W - 7W - 77 = 0
W(W + 11) - 7(W + 11) = 0
W - 7 = 0 or W + 11 = 0
W = 7 or W = - 11
Since the width cannot be negative, then W = 7cm
L = 77/7 = 11 cm
