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Lunna [17]
3 years ago
10

Plzzzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
luda_lava [24]3 years ago
5 0

a) 4p+2p-3p

=> 6p-3p

=> 3p

b) 9s-5s+2s-s

=> 4s+1s

=> 5s

c) 8t+3r-7t-9r

=>8t-7t-9+3

=> t-6r

Hope it helps!

kompoz [17]3 years ago
4 0

Answer:

3p , 5s , t - 6r

Step-by-step explanation:

(a)

4p + 2p - 3p ← add the first 2 terms

= 6p - 3p

= 3p

(b)

9s - 5s + 2s - s

= 4s + 2s - s

= 6s - s

= 5s

(c)

8t + 3r - 7t - 9r ← collect like terms

= (8t - 7t) + (3r - 9r)

= t - 6r

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Step-by-step explanation:

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You can use the definition:

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Then the derivative is

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I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

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and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

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