All categories

3 years ago

2.5047754593 rounded 4 decimal places

Mathematics

2 answers:

skad [1K]3 years ago

6 0

Answer:

2.5048

Step-by-step explanation:

the fourth decimal place of 2.5047754593 is the first seven.

to round take the next decimal to the right of the seven and determine if it is 0-4 or 5-9. in this case it is 7 so it will go in the second catagory

so that means to round up instead of keeping the same number. so the seven becomes an eight and the rest of the numbers go away

hope i explained well! :)

vfiekz [6]3 years ago

5 0

Answer:

2.5048

Step-by-step explanation:

Hope this helped!

You might be interested in

Please help me. Please!!

Y_Kistochka [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve for xxx. Your answer must be simplified. -4+x≤9

Degger [83]

Answer:

x≤13

Step-by-step explanation:

-4+x≤9

Add 4 to each side

-4+4+x≤9+4

x≤13

5 0

3 years ago

Im so confused rn i have no idea how to do this my teacher didnt teach us this

dimulka [17.4K]

Answer:

you use the mean method. and then round.

8 0

3 years ago

Read 2 more answers

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago

If two cards are drawn out of a deck WITH replacement, what's the probability that you draw a red card and then an Ace? ** Remem

katen-ka-za [31]

Answer:

Step-by-step explanation:

The probability of drawing a red card is 1/2, since half of the cards in a deck are red. The probability of drawing an ace from a deck is 1/13, since there is an equal chance to pick any of the 13 numbers.

P(red card and ace)= P(red card)*P(ace)=1/2 * 1/13=1/26

4 0

4 years ago

2.5047754593 rounded 4 decimal places​

2.5047754593 rounded 4 decimal places