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Elanso [62]
3 years ago
9

Can someone tell me how to get the answer???

Mathematics
2 answers:
lozanna [386]3 years ago
5 0
22.5m trust me hope this helps
Drupady [299]3 years ago
3 0

Answer:

22.5 cm

Step-by-step explanation:

In the figure attached the graph of the problem can be seen.

Given the triangles are similar then the next proportion must be satisfied:

13.5/9 = 18/12 = x/15 = 1.5

Isolating x, we get:

x/15 = 1.5

x = 1.5*15

x = 22.5 cm

This isn't my work. Thanks to jbiain.

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3 years ago
The relationship between the amount of money x that Cannon Precision Instruments spends on advertising and the company's total s
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Answer:

S'(x)=-0.006x2+0.8x+9

Step-by-step explanation:

The rate of change of the sales S(x) with respect to the amount of money spent on advertising x is then the derivative of S(x) with respect to x. What we have to calculate is S'(x).

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S'(x)=(−0.002x3 + 0.4x2 + 9x + 500)'=(−0.002)(3)x2 + (0.4)(2)x + 9

Which means:

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3 years ago
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot
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Answer:

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

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Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

\hat p=0.66 estimated proportion of voters that favored construction

p_o=0.63 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:  

Null hypothesis:p \leq 0.63  

Alternative hypothesis:p > 0.63  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562  

Statistical decision  

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The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

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