IF you mean

, then the following would be a solution:
First add 16 to both sides of the equation:

Now divide both sides of the equation by 3:

Take the square root of both sides to solve for "X", or simply solve by inspection: "what number(s) can be squared to get 49?"
Answer: -7 and 7 So the smallest solution would be "-7"
Answer:

Step-by-step explanation:
Given: 8x² + 10x - 7 = 0
<u>When factoring trinomials of the form ax² + bx + c</u>:
- multiply the leading coefficient and the last term.
- find the product factors that add to give you the coefficient of the middle term.
- rewrite the polynomial with those factors replacing the middle term.
1. Split the middle term:
⇒ 8 × -7 = -56 [multiply the leading coefficient and the last term]
⇒ 14, -4 [find the product factors that add to the middle term's coefficient]
⇒ 8x² + 14x - 4x - 7 = 0 [rewrite with those factors replacing the middle term.]
2. Factor by grouping:
⇒ 8x² + 14x - 4x - 7 = 0 [factor out 2x]
⇒ 2x(4x + 7) - 4x - 7 = 0 [factor out -1 or the negative sign]
⇒ 2x(4x + 7) -1(4x + 7) = 0 [factor out 4x + 7]
⟹ (4x + 7)(2x - 1) = 0
3. Separate into 2 cases:
- 4x + 7 = 0
- 2x - 1 = 0
<u><em>Case 1:</em></u>
⇒ 4x + 7 = 0 [subtract 7 from both sides]
⇒ 4x + 7 - 7 = 0 - 7
⇒ 4x = -7 [divide both sides by 4]
⇒ 4x ÷ 4 = -7 ÷ 4
⟹ x = 
<u><em>Case 2:</em></u>
⇒ 2x - 1 = 0 [subtract 1 from both sides]
⇒ 2x - 1 + 1 = 0 + 1
⇒ 2x = 1 [divide both sides by 2]
⇒ 2x ÷ 2 = 1 ÷ 2
⟹ x = 
Solutions:

Learn more about quadratic equations here:
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Answer:
Step-by-step explanation:
Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.
The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...
gardener's drawing = (1/4)actual size
actual size = 4(gardener's drawing)
__
The partner's drawing is 1/20 of actual size, so is ...
partner's drawing = actual size/20 = (4(gardener's drawing))/20
partner's drawing = (4/20)(gardener's drawing)
partner's drawing = (gardener's drawing)/5
__
Then the {length, width} of the partner's drawing are ...
partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}
The partner's drawing has a length of 3 inches and a width of 2 inches.
Answer:
26 mph
Step-by-step explanation:
d/t = r (distance/ time = rate)
104/4 = 26
Answer:
B) y² = 4x; There are two outputs for each input
Step-by-step explanation:
For an equation to be called a function, the input values for x must only result in a single output for y.
Based on this definition if a function, the functions y = x², y = -x and y = x are all functions because for any value of x imputed in them, we can only get one equivalent value of y.
The only exception is the function y²= 4x
For this function, for any value of x, there will be more than one output for y. Take x = 1 for example
y² = 4(1)
y² = 4
y = ±√4
y = ±2
This shows that y = 2 and -2
Also if x = 4
y² = 4(4)
y² = 16
y = ±√16
y = ±4
y = 4 and -4
No matter the value of x imputed, the output value y will always be two (a positive and a negative value)
Hence, option B is correct.