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wolverine [178]
3 years ago
10

Clark mows lawns for $8 each. He is able to mow 3 lawns a day. Part A: Let N represent the number of days Clark mows lawns. Writ

e an expression to show how much money Clark can earn mowing lawns. Part B: Use the expression from Part A to show how much money Clark would earn if he mowed lawns for 7 days.
Mathematics
2 answers:
babymother [125]3 years ago
4 0

Answer:

8n= $ He makes

Step-by-step explanation:

8 dollars is our unit rate, so it makes sense to multiply it by the N.

harkovskaia [24]3 years ago
3 0

Answer:

A: $8xN= $25  (N=5 days)

B: $8xN= $56 (N= 7 days)

Step-by-step explanation:

Hope This Helps! ;)

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Write a word problem for n($25)=$125​
velikii [3]
Julie bought (n) shirts. Each shirt cost $25. The total amount Julie spent on shirts was $125. How many shirts did Julie buy?
5 0
3 years ago
Match each exponential function to the description of its percent rate of change. 22% growth 12% decay 2% decay 20% growth 20% d
makvit [3.9K]

The exponential function is defined as y = a(1+r)^x, where "a" represents the original account and "r" the rate of growth or decay.

Then we have the following:

1) 22% grow

y = a( 1 + 22%/100 )^x = a(1.22)^x

So the solution is: 124(1.22)^x

2) 12% decay

y = a( 1 - 12%/100 )^x = a(0.88)^x

So the solution is: y = f(x) = 44(0.88)^x

3) 20% decay

y = a( 1 - 20%/100 )^x = a(0.8)^x

So the solution is: f(x) = 22(0.8)

4) 12% Groth

y = a( 1 + 12%/100 )^x = a(1.12)^x

So the solution is: f(x) = 42(1.12)^x

4 0
3 years ago
A stack of magazines is 4 2/5 inches high. Each magazine is 2/5 inch thick.
oee [108]

Answer:

Equation:(4 2/5)/2/5=? ; estimate: a

little more than 10 magazines; answer:

11 magazines in the stack.

Step-by-step explanation:

7 0
2 years ago
Let L be a tangent line to the hyperbola x y = 2 at x = 9 . Find the area of the triangle bounded by L and the coordinate axes.
mafiozo [28]

Answer:

A = 4

Step-by-step explanation:

The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:

y = \frac{2}{x}

y'=-2\cdot x^{-2}

The numerical value of the slope is:

y' = -2 \cdot (9)^{-2}\\y' = -\frac{2}{81}

The component of the y-axis is:

y = \frac{2}{9}

Now, the tangent line has the following mathematical model:

y = m \cdot x + b

The value of the intercept is found by isolating it within the equation and replacing all known variables:

b = y - m \cdot x

b = \frac{2}{9}-(-\frac{2}{81} )\cdot (9)\\b = \frac{4}{9}

Thus, the tangent line is:

y = -\frac{2}{81}\cdot x + \frac{4}{9}

The vertical distance between a point of the tangent line and the origin is given by the intercept.

d_{y} = \frac{4}{9}

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:

-\frac{2}{81}\cdot x + \frac{4}{9}=0

-\frac{2}{9}\cdot x + 4 = 0

x = 18

d_{x} = 18

The area of the triangle is computed by this formula:

A = \frac{1}{2}\cdot d_{x}\cdot d_{y}

A = \frac{1}{2}\cdot (18)\cdot (\frac{4}{9} )

A = 4

4 0
3 years ago
Solve the following equation: lim x->0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
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