Answer:
Roughly 16 million bacteria.
Step-by-step explanation:
Multiply the rate of the bacteria going through mitosis times the amount of daughter cells per hour, for this case.
<em>r x (m)ms x hr</em> <em>= </em>bacteria in one day
Hope this helps!
<em>note: ms and hr are millisecond and hour</em>
Answer:
63m^11 no^12
Step-by-step explanation:
Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation
(7nm^5 o^2) × (-3m^3 o^5)^2
7m^5 no^2) ×(-3m^3 o^5) ^2
(7m^5 no^2) × (3m^3 o^5)^2
7m^5 no^2 × (3m^3 o^5) ^2
7m^5 no^2 × 9m^6 o^10
63m^11 no^12
To figure this out youll have to multiply 64.80 by 2.5 first then youll get 162 after to figure out the answer you subtract 20 from that amount and get 142
I think the answer is the second one! Hope this helps!
Answer:
a. proportions have not changed significantly
Step-by-step explanation:
Given
Business College= 35 %
Arts College= 35 %
Education College = 30%
Calculated
Business College = 90/300= 9/30= 0.3 or 30%
Arts College= 120/300= 12/30= 2/5= 0.4 or 40%
Education College= 90/300= 9/30 = 0.3 or 30%
First we find the mean and variance of the three colleges using the formulas :
Mean = np
Standard Deviation= s= 
Business College
Mean = np =300*0.3= 90
Standard Deviation= s=
=
= 7.94
Arts College
Mean = np =300*0.4= 120
Standard Deviation= s=
=
= 8.49
Education College
Mean = np =300*0.3= 90
Standard Deviation= s=
=
= 7.94
Now calculating the previous means with the same number of students
Business College
Mean = np =300*0.35= 105
Arts College
Mean = np =300*0.35= 105
Education College:
Mean = np =300*0.3= 90
Now formulate the null and alternative hypothesis
Business College
90≤ Mean≥105
Arts College
105 ≤ Mean≥ 120
Education College
U0 : mean= 90 U1: mean ≠ 90
From these we conclude that the proportions have not changed significantly meaning that it falls outside the critical region.