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kompoz [17]
2 years ago
9

At a garden center grass seeds sell for $8 per pound. Kalil spent $10 on grass seed. What amount of seed did he buy

Mathematics
1 answer:
Brut [27]2 years ago
7 0
Kalil bought 1 pound and 1/4. ( 1 1/4)  It means: 1 pound and a quarter pound.
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2 years ago
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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
2 years ago
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timofeeve [1]
The distance formula is the square root of (X2 - X1)^2 + (y2 - y1)^2. Let D = y and c = x. Plug in the numbers now. Your equation is now the square root of ( -3 - (-5)) ^2 + (-2 - (-4))^2. Now complete it, your answer is 2.82...
8 0
2 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 36 and 2304, respectively.
poizon [28]

Answer:

a_n=9(4^{n-1})

Step-by-step explanation:

we know that

In a <u>Geometric Sequence</u> each term is found by multiplying the previous term by a constant, called the common ratio (r)

In this problem we have

a_2=36\\ a_5=2,304

Remember that

a_2=a_1(r) -----> 36=a_1(r) -----> equation A

a_5=a_4(r)

a_5=a_3(r^{2})

a_5=a_2(r^{3})

Substitute the values of a_5 and a_2 and solve for r

2,304=36(r^{3})

r^{3}=2,304/36

r^{3}=64

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Find the value of a_1 in equation A

36=a_1(4)

a_1=9

therefore

The explicit rule for the nth term is

a_n=a_1(r^{n-1})

substitute

a_n=9(4^{n-1})

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2 years ago
Can someone help me with this
sammy [17]

Answer:

Step-by-step explanation:

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