1. Identify each part of the exponent: (-4)3 Base = Exponent =

For the high school's production of "Grease," 490 tickets were sold. The cost of a student

damaskus [11]

The system of equations could be used to determine the number of each type of ticket sold is:

s + p + t = 490

8s + 10p + 12t = 4600

s + p = 6t

Number of each type of ticket sold is:

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

Solution:

Let "s" be the number of student tickets sold

Let "p" be the number of pre-sale non student ticket sold

Let "t" be the number of ticket sold at door

Cost of 1 student ticket = $ 8

Cost of 1 pre-sale non student ticket = $ 10

Cost of 1 ticket sold at door = $ 12

From given information,

490 tickets were sold. So we can frame a equation as:

number of student tickets sold + number of pre-sale non student ticket sold + number of ticket sold at door = 490

s + p + t = 490 ---------- eqn 1

Also given that, The total income from ticket sales was $4600

So we can frame a equation as:

number of student tickets sold x Cost of 1 student ticket + number of pre-sale non student ticket sold x Cost of 1 pre-sale non student ticket + number of ticket sold at door x Cost of 1 ticket sold at door = $ 4600

$s \times 8 + p \times 10 + t \times 12 = 4600$

8s + 10p + 12t = 4600 ------ eqn 2

The combined number of student and pre-sale tickets was 6 times more than the tickets sold at the door

s + p = 6t --------- eqn 3

So eqn 1 eqn 2 and eqn 3 could be used to determine the number of each type of ticket sold

Let us solve eqn 1, eqn 2, eqn 3 to find values of "s" "p" and "t"

Substitute eqn 3 in eqn 1

6t + t = 490

7t = 490

Substitute t = 70 in eqn 2

8s + 10p + 12(70) = 4600

8s + 10p = 3760 ----- eqn 4

Substitute t = 70 in eqn 3

s + p = 6(70)

s + p = 420 ----- eqn 5

Multiply eqn 5 by 8

8s + 8p = 3360 ----- eqn 6

Subtract eqn 6 from eqn 4

8s + 10p = 3760

8s + 8p = 3360

(-) ---------------------

2p = 400

Substitute p = 200 in eqn 5

s + 200 = 420

Summarizing the results:

number of student tickets sold = 220

number of pre-sale non student ticket sold = 200

number of ticket sold at door = 70

3 0

3 years ago

Solve for x in this equation: 3/4+ |5-x| = 13/4

Rom4ik [11]

Answer:

x = 2.5 or 7.5

Step-by-step explanation:

Subtract 3/4.

|5 -x| = 10/4 = 2.5

This resolves to two equations:

5 -x = 2.5 ⇒ x = 5 -2.5 = 2.5
5 -x = -2.5 ⇒ x = 5 +2.5 = 7.5

The solutions are x = 2.5 or 7.5.

5 0

3 years ago

in class 9th A number of boys is 5 more than number of girls and 3 times of number of girls is 12 more than double the number of

dedylja [7]

Let the number of boys be x
Let the number of girls be y

x＝y＋5
3y＝2x＋12

3y＝2(y＋5)＋12

y＝22

3×22＝2x＋12

x＝27

(x, y)＝(27, 22)

There are 27 boys and 22 girls.

Hope my answer helped u :)

5 0

3 years ago

Solve f(2) for f(x)=x-51 f(2)= [?]

givi [52]

Plug in 2 for x. f(20=2-51 = -49

5 0

4 years ago

Read 2 more answers

To pass a course with a C grade, a student must have an average of 70 or greater. A student's grades on three tests are 69, 77 a

Genrish500 [490]

Answer:

Grade≥69(at least 69)