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3 years ago

What is the circumcenter

Mathematics

2 answers:

dolphi86 [110]3 years ago

7 0

The center of a circumference

34kurt3 years ago

6 0

The circumcenter is the center of a triangle's circumcircle. It can be found as the intersection of the perpendicular bisectors.

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the window of a room is 20m long and 14m wide. if the carpenter works to put a metallic frame around it which cost Rs.120 per me

notka56 [123]

Answer:

33,600

Step-by-step explanation:

length=20m

wide=14m

area= 28m²

1m= 28

cost = 120*28= rs33600 per m²

3 0

3 years ago

Please help brainliest giveaway

Vikentia [17]

Answer:

Hey, just here so he can get brainliest, have a nice day!

Step-by-step explanation:

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3 years ago

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Teen obesity:

Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample % of U.S. public high school students who were obese = 15%

n = sample of U.S. public high school students = 300

p = population percentage of all U.S. public high school students

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ , $0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ ]

= [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

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3 years ago

Caleb will be going to college next year. He would like to save some money for living expenses. Select the goal that would be th

Rina8888 [55]

Answer:

save 100$ each check.

Step-by-step explanation:

8 0

3 years ago

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Which of the following could represent the graph of f(x)=x^3-x^2-6x?

Ksenya-84 [330]

I think it's the first one

7 0

3 years ago

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