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gladu [14]
3 years ago
8

Developed the first form of our abstract symbolic language.

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

what? do you mean by that

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find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next
zalisa [80]

Answer:

The number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

Step-by-step explanation:

We need to find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​.

There are 9 letters in the word WONDERFUL

There is a condition that letter R is always next to E.

So, We have two letters fixed WONDFUL (ER)

We will apply Permutations to find ways of arrangements.

The 7 letters (WONDFUL) can be arranged in ways : ⁷P₇ = 7! = 5040 ways

The 2 letters (ER) can be arranged in ways: ²P₂ =2! = 2 ways

The number of ways 'WONDERFUL' can be arranged is: (5040*2) = 10,080 ways

So, the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

8 0
3 years ago
Help me please k12..
34kurt

Answer: It's 8

Step-by-step explanation:

4 0
3 years ago
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Consider the quadratic function f(x)=8x2- 7x+6. What is the constant of the function?
Ostrovityanka [42]

Answer:

Step-by-step explanation:

it is 6

6 0
3 years ago
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HELP PLEASEEEE I WILL AWARD 100 POINTS ITS DUE ASAPPP<br> What is the equation for A(w)=?
skad [1K]

Answer:

390=W 195=L Area=76050

Step-by-step explanation:

You have two lengths and one width for your perimeter

P= 2L + W

you are given your perimiter 780

780= 2L + W

To solve for your maximum Width

780-2L=w

Area is L * W

A= (780-2L)*L

A= 780L - 2L^2

the derivitive of the Area

A' = 780-4L =0

add 4L to both sides

780=4L

divide by 4 on both sides

195=L

Bring back 780-2L=W and plug in what you now know is L

780-2(195)=W

780-390=W

390=W

7 0
3 years ago
What is the vertex form of the equation <br> Y=-x^2-12x-4<br> Please show all the steps
denis-greek [22]

Answer:

              \boxed{\bold{y=-(x+6)^2+32}}

Step-by-step explanation:

y=-x^2-12x-4\\\\y=-(x^2+12x)-4\\\\y=-(\underline{x^2+2\cdot x\cdot6+6^2}-6^2)-4\\\\y=-\left[(x+6)^2-36\right]-4\\\\y=-(x+6)^2+36-4\\\\\bold{\underline{y=-(x+6)^2+32}}

5 0
3 years ago
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