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goldenfox [79]
3 years ago
10

1 point

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

IQR = 20

Step-by-step explanation:

Quartile 1 = 25

Quartile 3 = 45

To find the interquartile range, take Q3 from Q1

45 - 25 = 20 .

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System of equations <br> 5x+y=7<br> 20x+2=y
KIM [24]
Dependent

The general form for a pair of linear equations in two variables x and y is
and

----- (1)
----- (2)
Comparing equations 1 and 2 with the general form of equation to write their co-efficient,

Compare the ratio,

If , then the pair of linear equations has exactly one solution.
So, it said to be consistent.
7 0
4 years ago
22.857142857142858 As a fraction
Mamont248 [21]

Answer:

Step-by-step explanation:

1. The answer is 8/35.

2. This works because 8/35 equals 22.857142857142858.

Please give me brainliest, I really need it! Thank you!

5 0
1 year ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
(04.01 MC)
levacccp [35]

9514 1404 393

Answer:

  {(0, −5), (2, 9), (−3, −26)}

Step-by-step explanation:

You only need to try the first point in each set to eliminate the wrong answers.

a: 7(-5)-5 = -40 ≠ 0

b: 7(2)-5 = 9 ≠ 7

c: 7(0)-5 = -5 . . . matches given point

d: 7(1)-5 = 2 ≠ 3

The third choice is the correct one: {(0, −5), (2, 9), (−3, −26)}.

8 0
3 years ago
Can some one help me please
GREYUIT [131]

Answer:

Acc to the exponential rule

{[A^m]} ^2

A ^m*n

Hence A raise to 3 whole raise to 2 is equal to

A raise to 3*2=6

That is A raise to 6

4 0
3 years ago
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