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Svet_ta [14]
2 years ago
12

How do you solve this step-by-step?

Mathematics
1 answer:
gtnhenbr [62]2 years ago
4 0

Answer:

  • 7 1/20

<u>OAmalOHopeO</u>

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Your employer has 600 business cards printed for you, and you give away 280 of them. To the nearest hundredth, what percent of t
Ulleksa [173]
If you gave away 280 of 600 business cards and you would like to know what percent of the cards is left, you can calculate this using the following steps:

600 - 280 = 320 cards are left

320 / 600 = 8 / 15 = 0.5333 = 53.33%

The correct result is D. 53.33%.
7 0
3 years ago
Read 2 more answers
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Find the largest 4-digit number which is a perfect square.
pickupchik [31]

Answer:

<em><u>To find the biggest 4-digit number which is a perfect square, we have to take the square of biggest 2-digit number. ∴ The biggest 4-digit number which is a perfect square = 9801.</u></em>

Step-by-step explanation:

<h2>mark as brainlest answer </h2>
6 0
2 years ago
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Each student in a classroom has chosen either a green, red, or blue marble and written their initials on it. In addition, some o
scoundrel [369]
A. 2/5 B. 1/3 just like the other person said lol
7 0
3 years ago
9. Select a set of corresponding angles.
Anettt [7]

Answer:

A. Angles M and D

3 0
3 years ago
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