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ch4aika [34]
3 years ago
10

Alexa is deciding where to buy a new camera. Each store offers a 1-year loan for $450 but with different interest rates and fees

. Which is the best way for Alexa to choose the $450 loan that will cost her the LEAST?
Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

The Loan with the lowest annual percentage rate (APR)

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The product of twice a number and six is the same as the difference of eleven times the number and 1/4 fine the number
solmaris [256]

Answer:

x= -1/4

Step-by-step explanation:

suppose ,

The  number is x

now,

twice a number = 2 . x = 2x

The product of twice a number and six = 2x . 6 = 12x

  [ "product" means the result of multiplication]

Then,

Eleven times the number = 11 . x = 11x

The difference of eleven times the number and 1/4 = 11x - 1/4

                                                                                       =  (44x-1)/4

Hence,

 12x = (44x-1)/4

=>48x = 44x-1        [multiplied by 4 on both sides]    

=>48x-44x=-1         [subtract 44x on both sides]    

=>4x=-1                   [divide both sides by 4]  

=>x= -1/4                              

3 0
3 years ago
A parabola is given by the equation y = x2 + 4x + 4.
notsponge [240]

Answer:

the vertex of the parabola is:(-2,0)

the focus of the parabola is:(-2,\frac{1}{4})

the directrix of the parabola is:y=\frac{-1}{4}

Step-by-step explanation:

we know that for any general equation of the parabola of the type y=ax^{2} +b x+c the vertex of the parabola is given by (h,k)

where h=\frac{-b}{2 a} and k=\frac{4 a c-b^{2} }{4a}

therefore by the given data we have h=-2 and k=0

hence vertex=(-2,0)

the general equation of the parabola of the type 4 a (y-h)=(x-k)^2 ; the parabola symmetric around the y-axis has the focus from the centre i.e. the vertex (h,k) at a distance a as (h,k+a) and the directrix is given by y=k-a

so focus is (-2,\frac{1}{4} )

now the directrix of the parabola is y=\frac{-1}{4}.




3 0
3 years ago
Type the correct answer for each.
xxTIMURxx [149]
If point \left(x,\ \frac{\sqrt{7}}{3}\right) is on the unit ircle, then:

x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\  \\ \Rightarrow x^2+ \frac{7}{9} =1 \\  \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9}  \\  \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}

Since, the point is in the second quadrant, x is negative.

Thus, (x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)

Part A:

3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\  \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\  \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\  \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta

Therefore, -6\tan\theta=3\sqrt{7}.



Part B:

- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} }  \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x}  \\  \\ =\tan\theta

Therefore, \tan\theta=- \frac{ \sqrt{7} }{2}
8 0
3 years ago
Hank brought a fish tank
yaroslaw [1]
To find volume you do length*width*height
therefore it would be 15*8*10= 1,200
3 0
3 years ago
Can yall help me with this pls
Katyanochek1 [597]
Its the third answer, how much gas he has after one hour
7 0
2 years ago
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