Answer:
Step-by-step explanation:
Given
Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height
Suppose they have same mass and radius
time Period is given by
,where h=height of release
a=acceleration

Where I=moment of inertia
a for hoop


a for Uniform solid cylinder


a for spherical shell


a for Uniform Solid


time taken will be inversely proportional to the square root of acceleration




thus first one to reach is Solid Sphere
second is Uniform solid cylinder
third is Spherical Shell
Fourth is hoop
ANSWER: the man bought 5 shirts
Answer:
The answer to your question is 450 km
Step-by-step explanation:
Data
First stage Second stage
speed 1 = 40 km/h speed 2 = 65 km/h
time 1 = 8 h time 2 = 2 h
Process
1.- Write the formula to calculate the speed
speed = distance / time
-Solve for distance
distance = speed x time
2.- Calculate the distance of the first stage
distance 1 = 40 x 8
distance 1 = 320 km
3.- Calculate the distance of the second stage
distance 2 = 65 x 2
distance 2 = 130 km
4.- Calculate the total distance
Total distance = 320 + 130
= 450 km
Answer:
Step-by-step explanation:
202 students taking math and are business majors
only math, would be (861 - 202) = 659
only business majors, would be (525 - 202) = 323
so there are (659 + 323) = 982 that are math or business majors