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fenix001 [56]
3 years ago
9

I can Multiply a 4x4 matrix by a 4x3 matrix. The resulting matrix will be a?

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

21

Step-by-step explanation:

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If Angle 1 and Angle 2 are complementary angles and if the measure of Angle 1 is 20° more than the measure of Angle 2, determine
Ratling [72]
A) Ang 1 + Ang 2 = 90
B) Ang 1 = Ang 2 + 20
B) Ang 1  -Ang 2 = 20 then adding this to equation A produces
2 Ang1= 110
Ang 1 = 55 degrees
Ang 2 =35 degrees


8 0
3 years ago
I NEED ALGEBRA HELP! Can you solve a system of equations using the substitution by solving one equation for x or y and then usin
cricket20 [7]

Answer:

let x be y

NOW,

X+6Y=6

Y+6Y=6

7Y=6

Y=0.87

5 0
3 years ago
There’s actually two questions on here please help me
aev [14]

Problem 7

Time is always an independent variable because time marches on doing its own thing without depending on external forces, or other people/things. Instead, other variables depend on time. In this case, the distance d depends on the independent variable t for time.

If the time goes up by 1 hour, then the distance variable goes up by 3 miles. In short, that tells us his speed is 3 mph.

Answer: Choice A) independent = time; dependent = distance

=================================

Problem 8

Everywhere you see an x, replace it with 9. Then use PEMDAS to simplify

f(x) = 5x - 9

f(9) = 5(9) - 9 ... x replaced with 9

f(9) = 45 - 9

f(9) = 36

Answer: 36

4 0
3 years ago
Someone please help me with this math problem?
marishachu [46]

Answer:

The length of the shortest side of the triangle is 10 units.

Step-by-step explanation:

Let <em>a</em> be the shortest side of the isosceles triangle and <em>b</em> be the two congruent sides.

The congruent sides <em>b</em> are each one unit longer than the shortest side. Hence:

b=a+1

The perimeter of the isosceles triangle is given by:

\displaystyle P_{\Delta}=b+b+a=2b+a

This is equivalent to the perimeter of a square whose side lengths are two units shorter than the shortest side of the triangle. Let the side length of the square be <em>s</em>. Hence:

s=a-2

The perimeter of the square is:

\displaystyle P_{\text{square}}=4s=4(a-2)

Since the two perimeters are equivalent:

2b+a=4(a-2)

Substitute for <em>b: </em>

<em />2(a+1)+a=4(a-2)<em />

Solve for <em>a</em>. Distribute:

2a+2+a=4a-8

Simplify:

3a+2=4a-8

Hence:

a=10

The length of the shortest side of the triangle is 10 units.

4 0
3 years ago
el perimetro de un terreno rectangular es de 170m y su area es de 170^2hallar la medida de sus lados con ecuacion cuadratica
Blizzard [7]

Answer:

Acá tenemos un sistema de ecuaciones.

El perímetro de un rectángulo es:

2*A + 2*L = 170m

donde A es el ancho y L es el largo.

Y el área del rectángulo es:

A*L = 170m^2.

Entonces, el primer paso es aislar una de las variables en una de las ecuaciones, yo voy a aislar A en la segunda:

A = 170m^2/L.

Ahora reemplazo eso en la primera ecuación y la resuelvo para L.

2*( 170m^2/L.) + 2*L = 170m.

340m^2 + 2*L^2 = 170m*L

ahora tenemos una ecuación cuadrática:

2*L^2 - 170m*L + 340m^2 = 0.

Las soluciones se pueden obtener usando la formula de Bhaskara:

L = \frac{+170 +- \sqrt{170^2 -4*340*2}  }{2*2} = \frac{170 +-161.8}{4}

Entonces las soluciones son:

L = (170 + 161.8)/4 = 82.95m

L = (170 - 161.8)/4 = 4.1m

Entonces, si tomamos L = 82.95m, tenemos A = 4.1 m

y el área es:

A*L = 4.1m*82.95m = 170m^2

3 0
3 years ago
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