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kirill115 [55]
1 year ago
8

2x^3-16x^2-40x=0 factor

Mathematics
1 answer:
ExtremeBDS [4]1 year ago
3 0

The given expression is

2x^3-16x^2-40x=0

We extract the common factor 2x.

\begin{gathered} 2x(x^2-8x-20)=0 \\ 2x=0\rightarrow x=0 \\ x^2-8x-20=0 \end{gathered}

The first solution is 0.

Now, we solve the quadratic expression. We have to find two numbers whose product 20 and whose difference is 8. Those numbers are 10 and 2.

x^2-8x-20=(x-10)(x+2)<h2>Hence, the given expressions expressed, as factors, is</h2>2x^3-16x^2-40x=x(x-10)(x+2)

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