Question

2x^3-16x^2-40x=0 factor

Answer 1

The given expression is

$2x^3-16x^2-40x=0$

We extract the common factor 2x.

$\begin{gathered} 2x(x^2-8x-20)=0 \\ 2x=0\rightarrow x=0 \\ x^2-8x-20=0 \end{gathered}$

The first solution is 0.

Now, we solve the quadratic expression. We have to find two numbers whose product 20 and whose difference is 8. Those numbers are 10 and 2.

$x^2-8x-20=(x-10)(x+2)$

Hence, the given expressions expressed, as factors, is

$2x^3-16x^2-40x=x(x-10)(x+2)$