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nexus9112 [7]
3 years ago
6

rs%3F%7D" id="TexFormula1" title=" \large \tt \blue{What \: are \: prime \: numbers?}" alt=" \large \tt \blue{What \: are \: prime \: numbers?}" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
GrogVix [38]3 years ago
6 0
The numbers that are divisible by 1 and the number itself is called a prime number. Eg: 1,2,3,5,7,11,13,17,19
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hodyreva [135]
Yes because 15+8=23 divide that into a number that could each child have and just make it into equal amounts
7 0
3 years ago
Read 2 more answers
What is the minimum value of 2x + 2y in the feasible region?<br> (0,7) (3,7) (6,3) (6,0)
topjm [15]
Graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.
hence i would go for
<span>(6,3)</span>
8 0
3 years ago
Determine the measure of the missing angle in the figure below.
bearhunter [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin
seropon [69]

Answer:

Part a) The ratio of the perimeters is 3

Part b) The ratio of the areas is 9

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

z=\frac{x}{y}

we have

z=3

substitute

\frac{x}{y}=3

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

z^{2}=\frac{x}{y}

we have

z=3

substitute

\frac{x}{y}=3^{2}

\frac{x}{y}=9}

3 0
3 years ago
The function V=25000\left(0.82\right)^tV=25000(0.82) t models the depreciation of the value of a new car that originally cost $\
alekssr [168]

Answer:

V = 7,600.17

Step-by-step explanation:

Given:

V=25000(0.82)^t

Where,

V = value of the car

t = time in years

Find V when t = 6

V = 25,000(0.82)^t

= 25,000(0.82)^6

= 25,000(0.304006671424)

= 7,600.1667856

Approximately

V = 7,600.17

4 0
2 years ago
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