Yes because 15+8=23 divide that into a number that could each child have and just make it into equal amounts
Graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.
hence i would go for
<span>(6,3)</span>
Answer:
Step-by-step explanation:
Answer:
Part a) The ratio of the perimeters is 
Part b) The ratio of the areas is 
Step-by-step explanation:
Part A) What is the value of the ratio (new to original) of the perimeters?
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
z-----> the scale factor
x-----> the perimeter of the new triangle
y-----> the perimeter of the original triangle

we have

substitute

Part B) What is the value of the ratio (new to original) of the areas?
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> the area of the new triangle
y-----> the area of the original triangle

we have

substitute


Answer:
V = 7,600.17
Step-by-step explanation:
Given:
V=25000(0.82)^t
Where,
V = value of the car
t = time in years
Find V when t = 6
V = 25,000(0.82)^t
= 25,000(0.82)^6
= 25,000(0.304006671424)
= 7,600.1667856
Approximately
V = 7,600.17