10. A company manufactures photo cells. It uses the expression
2 answers:
the expression millimeters per second , after simplification we get
Given
The company uses the expression millimeters per second to calculate the maximum capacity with area
Lets apply the property of exponents to simplify the expression
We apply power property of exponents.
If we have exponent inside and outside the parenthesis then we multiply it
we distribute outside exponent inside the parenthesis
In the given expression , 2 has exponent 1
The simplified expression after applying the property is
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Answer:
a) The percentage of bone density scores that are significantly high is 2.28%
b) The percentage of bone density scores that are significantly low is 2.28%
c) The percentage of bone density scores that are not significant is 95.44%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
a. significantly high (or at least 2 standard deviations above the mean).
This is 1 subtracted by the pvalue of Z = 2.
Z = 2 has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% of scores are signifcantly high
b. significantly low (or at least 2 standard deviations below the mean).
pvalue of Z = -2
Z = -2 has a pvalue of 0.0228
2.28% of scores are signicantly low.
c. not significant (or less than 2 standard deviations away from the mean).
pvalue of Z = 2 subtracted by the pvalue of Z = -2.
Z = 2 has a pvalue of 0.9772
Z = -2 has a pvalue of 0.0228
0.9772 - 0.0228 = 0.9544
95.44% of the scores are not significant