They would have used a total of 30 horses. Each person would've each ridden 15 so 15+15= 30 and 165 divided by 11 is 15. Hope this is off help!
If im not wrong which i may not the
Dependent is A
Independent is B
With the given information, we can create several equations:
120 = 12x + 2y
150 = 10x + 10y
With x being the number of rose bushes, and y being the number of gardenias.
To find the values of the variables, we can use two methods: Substitution or Elimination
For this case, let us use elimination. To begin, let's be clear that we are going to be adding these equations together. Therefore, in order to get the value of one variable, we must cancel one of them out - it could be x or y, it doesn't matter which one you decide to cancel out. Let's cancel the x out:
We first need to multiply the equations by numbers that would cause the x's to cancel out - and this can be done as follows:
-10(120 = 12x + 2y)
12(150 = 10x + 10y) => Notice how one of these is negative
Multiply out:
-1200 = -120x - 20y
+ 1800 = 120x + 120y => Add these two equations together
---------------------------------
600 = 100y
Now we can solve for y:
y = 6
With this value of y known, we can then pick an equation from the beginning of the question, and plug y in to solve for x:
120 = 12x + 2y => 120 = 12x + 2(6)
Now we can solve for x:
120 = 12x + 12 => 108 = 12x
x = 9
So now we know that x = 9, and y = 6.
With rose bushes being x, we now know that the cost of 1 rose bush is $9.
With gardenias being y, we now know that the cost of 1 gardenia is $6.
Answer:
the solution for x will be given by {x| -13 < x < 13}
Therefore the correct option is B.
Step-by-step explanation:
i) given that |x| < 13
ii) therefore x < 13 for positive values of x
iii) for negative values of x we have -x < 13
therefore x > -13
iv) from ii) and iii) above we can conclude that the solution for x will be given by {x| -13 < x < 13}
Therefore the correct option is B.
Can u answer my question........Write a real world problem involving the multiplication of a fraction and a whole number with a product that is between 8 and 10. Then solve the problem.
