Answer:
0.0668 = 6.68% probability that the worker earns more than $8.00
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.
This means that
If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?
This is 1 subtracted by the pvalue of Z when X = 8. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the worker earns more than $8.00
Answer:
If 30 unicorns out of 300 walk away then it will be 300-30=270 unicorns left.
If 50 dragons fly away out of 200 then it will be 200-50=150.
Therefore there are 270 unicorns and 150 dragons left.
I hope this helps you...Thank you...
<span>Ans : a)
What is the standard deviation of this sampling distribution?
Ď /âšn
= 60/âš840
=2.0702
b)
1 standard deviation of the mean
= (1) 2.07
= 2.07
c)
272+/- 1(2.07)
(269.93, 274.07)</span>
Answer:
D
Step-by-step explanation:
Took the test on edge2020
<span>let x be the first integer, then
:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519
:
6x + 15 = 519
:
6x = 504
:
x = 84</span>