All categories

3 years ago

1. 0 f the 320 eighth

Mathematics

1 answer:

Kay [80]3 years ago

3 0

Answer:

There are 208 male students in the eight grade.

Step-by-step explanation:

320 students all together - 35% female students= 208 male students

You might be interested in

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

the original recipe for tartar sauce yields 1 gallon but you need to prepare 2 1/2? round the answer to the nearest hundredth de

Evgesh-ka [11]

I believe the answer is 2.5. I apologize if I'm wrong :/ =))

3 0

2 years ago

4. Part A. Find the value of x.

nirvana33 [79]

Part A: B)35
As the angle y° equals to angle 2x°, y=2x.
And the sum of the angle (x+y+5°)and the angle 2x° is 180°.Therefore,
x+y+5°+2x =180°
x+2x+5°+2x=180°
5x+5° =180°
5x =175°
x =35°

Part B: C)110°
As I said, y =2x
And the unlabled angle eaquals to the angle(x+y+5°).
Therefore,
the unabled angle= x+y+5°
=x+2x+5°
=3x+5°
=3(35°)+5°
=110°

3 0

3 years ago

Read 2 more answers

How do you factor: x^3 - 8 (x cubed minus 8)

Firlakuza [10]