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2 years ago

Which of the following expressions is correct?

Mathematics

1 answer:

AysviL [449]2 years ago

8 0

Answer:

-7.5x3+(20+2.5)=0

this one is equal to 0 ;)

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Jessie estiments the weight of her cat to be 10 pounds the actual weight of the cat is 13.75 pounds fine the percent error

GarryVolchara [31]

Answer:

The percent error would be 27.27%

Step-by-step explanation:

percent error = \frac{measured - actual}{actual} x 100%

3 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST PRECALC

nexus9112 [7]

Answer:

$270^o$ and $450^o$

Step-by-step explanation:

Recall that $\frac{\sqrt{2} }{2}$ is a value of the function cosine for the special angles: $135^o$ and $225^o$ , then:

$\frac{x}{2} =135^o\\x=270^o\\or\\ \frac{x}{2} =225^o\\x=450^o\\$

4 0

3 years ago

Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

tankabanditka [31]

5k3-3k+7-(-2k3+k2-9)
basically rewrite with simple algebra principles
15k-3k+7-(-6k+2k-9)
split up the parenthesis
15k-3k+7+6k-2k+9
sort them
15k-3k+6k-3k+7+9
short down by adding up the similar factors
answer: 18k+18
factorise
18(k+1)
both forms are right

8 0

3 years ago

Read 2 more answers

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$