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Levart [38]
2 years ago
15

Which of the following expressions is correct?

Mathematics
1 answer:
AysviL [449]2 years ago
8 0

Answer:

-7.5x3+(20+2.5)=0

this one is equal to 0 ;)

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A roulette wheel has 38 pockets numbered 0,00,and 1 to 36. Of all 38 pockets 18 are red, 18 are black and 2 are green. Each time
Fiesta28 [93]

Answer:

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

Step-by-step explanation:

Each spin is independent of the others, so the probabilities of the three possible outcomes (R,G,B) for each spin are:

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

4 0
2 years ago
PLEASE HELP VERY IMPORTANT I REALLY NEEDS HELP
strojnjashka [21]
[see picture link]Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Picture: https://us-static.z-dn.net/files/d30/9033549987fa60cf57fe05f71424f322.gif
6 0
3 years ago
PLZ help thnx
Pepsi [2]

Answer:

A) $40

B) 40M = P

C)  $3,120

Step-by-step explanation:

Given that at her salon, last week Tammy did 25 manicures and collected $ 1000, to calculate the slope to represent the manicures, write an equation to represent this relation and determine how much would Tammy make if she did 78 manicures in a month the following calculations should be performed:

A)

1000/25 = X

40 = X

Thus, each manicure costs $ 40.

B)

40M = P

C)

78 x 40 = X

3.120 = X

So if she did 78 manicures in a month, Tammy would earn $ 3,120.

8 0
2 years ago
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 76 torr/h , what is the rate of change f
fiasKO [112]

The reaction is missing and it's ;

N2H4 + H2 ---> 2NH3

It asks for the total pressure too.

Answer:

A) Rate of change for NH3 = 152 torr/h

B) The total pressure in the vessel will remain the same.

Step-by-step explanation:

N2H4 + H2 ---> 2NH3

1 mole of N2H4 yields 2 moles of NH3.

From the question, the rate given for N2H4 is 76 torr/h.

Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h

Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.

While on the product side, 2 moles of NH3 are produced.

So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.

3 0
3 years ago
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