Answer:
If you roll two dices, you can get as results all numbers from 2 to 12. Among these, the prime numbers are 2, 3, 5, 7, 11. The probability you get each of them is: 2: you can get it only as 1+1, so one combination over 36 possibility. Probability: 1/36. 3: you can get it as 1+2 or 2+1, so two combinations over 36 possibility. Probability: 2/36. 5: you can get it as 1+4, 2+3, 3+2, 4+1, so four combinations over 36 possibility. Probability: 4/36. 7: you can get as 1+6, 2+5, 3+4, 4+3, 5+2, 6+1, so six combinations over 36 possibility. Probability: 6/36. 11: you can get it as 5+6 or 6+5 so two combinations over 36 possibility. Probability: 2/36. The total probability of getting a prime number is the sum of the probabilities, which is 15/36. So m=15, n=36 and 10m+n=150+36=186.
Answer:
a, y =3/x
x = 0.5 => y = 3/0.5 = 6
x = 1 => y = 3/1 = 3
x = 2 => y = 3/2 = 1.5
x = 3 => y = 3/3 = 1
x = 4 => y = 3/4 = 0.75
b,
y = 3/x passes (0.5, 6) => A is correct
Hope this helps!
