![f(0) = {4}^{3 \times 0 + 3} = {4}^{0 + 3} = {4}^{3} = 64](https://tex.z-dn.net/?f=f%280%29%20%3D%20%20%7B4%7D%5E%7B3%20%5Ctimes%200%20%20%2B%203%7D%20%20%3D%20%20%7B4%7D%5E%7B0%20%2B%203%7D%20%20%3D%20%20%7B4%7D%5E%7B3%7D%20%20%3D%2064)
The answer is above.
Additional note 1:
![{4}^{3} = 4 \times 4 \times 4 = 16 \times 4 = 64](https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B3%7D%20%20%3D%204%20%5Ctimes%204%20%5Ctimes%204%20%3D%2016%20%5Ctimes%204%20%3D%2064)
Additional note 2:
In the answer I filled in "0" at the place where "n" was. This is because the question tells us n=0
I’m pretty sure it’s the first one cause it’s half of the 6 blocks
First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
![24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )](https://tex.z-dn.net/?f=24%285%29%20%2B%2024%28%20%5Cfrac%7Bx%20-%202%7D%7B3%7D%20%29%20%3D%2024%28%20%5Cfrac%7Bx%20%2B%203%7D%7B8%7D%20%29)
This will give you,
![120 + 8(x - 2) = 3(x + 3)](https://tex.z-dn.net/?f=120%20%2B%208%28x%20-%202%29%20%3D%203%28x%20%2B%203%29)
Then just continue to simplify and isolate the variable.
![120 + 8x - 16 = 3x + 9](https://tex.z-dn.net/?f=120%20%2B%208x%20-%2016%20%3D%203x%20%2B%209)
![8x + 104 = 3x + 9](https://tex.z-dn.net/?f=8x%20%2B%20104%20%3D%203x%20%2B%209)
![5x = - 95](https://tex.z-dn.net/?f=5x%20%3D%20%20-%2095)
Answer:
3 more than
Step-by-step explanation:
Hope this correct and Your welcome