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3 years ago

5

The line parallel to y=9x+4 that passes through (2,7)

1 answer:

Andreas93 [3]3 years ago

8 0

Y = 9x + 4....the slope here is 9. A parallel line will have the same slope

y = mx + b
slope(m) = 9
(2,7)...x = 2 and y = 7
now we sub into the formula and find b, the y int
7 = 9(2) + b
7 = 18 + b
7 - 18 = b
-11 = b

so ur parallel equation is : y = 9x - 11 <==

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What value represents the number of ways in which the expected classes are free to vary in the chi-square goodness-of-fit test?

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3 years ago

Determine the reveune for selling 500 helmets

Tasya [4]

Answer:

x is the price the helmets were sold at.

y is the business expenses.

r is the revenue.

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Step-by-step explanation:

500x - y = r

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3 years ago

In ABC, side BC is extended to point E. When connected to vertex A, segment EA is parallel to segment BD. In this construction,

Anuta_ua [19.1K]

Two triangles are said to be <u>congruent</u> if they have <em>similar</em> properties. Thus the required <u>options</u> to complete the <em>paragraph proof</em> are:

a. angle 1 is <u>congruent</u> to angle 2.

b. <em>alternate</em> angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.

c. $\frac{AD}{CD}$ = $\frac{AB}{CB}$

The <em>similarity property</em> of two or more shapes implies that the <u>shapes</u> are congruent. Thus they have the <em>same</em> properties.

From the given <u>diagram</u> in the question, it can be deduced that

ΔABC ≅ ΔABE (<em>substitution</em> property of equality)

Given that EA is <u>parallel</u> to BD, then:

i. <2 ≅ <3 (<em>corresponding</em> angle property)

ii. <1 ≅ < 4 (<em>alternate</em> angle property)

Thus, the required options to complete the <em>paragraph proof</em> are:

Angle 1 is <em>congruent</em> to angle 2.
Alternate angles are <u>congruent</u> if two parallel lines are cut by a <em>transversal</em>.
$\frac{AD}{CD}$ = $\frac{AB}{CB}$

For more clarifications on the properties of congruent triangles, visit: brainly.com/question/1619927

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2 years ago

Please help, very much needed. Thanks, oh and I give brainliest!

kramer

Answer:

D I think

Step-by-step explanation:

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3 years ago

Read 2 more answers

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe

timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

$EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5$

So,

$EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1$

And

$GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)$

Now

$FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\ ..... (2)$

Solving (1) and (2)

b = - 2 ,

$a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6$

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3 years ago