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3 years ago

Which expression was factored completely using the GCF, if the original expression was

Mathematics

2 answers:

amid [387]3 years ago

7 0

Answer:

4x iss the GCF that was factored out.

Step-by-step explanation:

Given the equation 4x²+8x, the greatest common factor will be the maximum factor of 4x² and 8x and that is 4x. Factoring out 4x from the given equation will result into the equation;

4x(x+2)

Note that the the resulting value in the bracket must have no other common factor after the GCF must have been factored out.

Therefore the expression that was factored out using GCF was 4x

Lerok [7]3 years ago

4 0

Answer:

4x(x+2)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Since this is a right triangle, we can use trig functions

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sin A = 12/13

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3 years ago

2 + 1/6a = -4 what is a

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3 years ago

Which is steeper, a slide that rises 3 feet for every 2 feet run, or a sliding pole that rises 5feet for every 3feet run

igor_vitrenko [27]

The sliding pole is steeper. (rise/run) 5/3 (1.666) is greater than 3/2 (1.5).

4 0

3 years ago

When I double my number add 4 and then subtract my number and subtract three I get my number plus one what is my number?

Lady bird [3.3K]

2 because once you double it, it becomes 4. Once you add 4, you get 8. When you subtract your number, which is 2, you get 6. Then when you subtract 3, you get 3. 3 is your number (2) plus 1

5 0

3 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

4 years ago