49/8 as a mixed number
1 answer:
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<h2>Answer : (2.67, 3.53)</h2><h2></h2>
Step to step explanation:
Confidence interval for mean, when population standard deviation is unknown:
, where = sample mean
n= sample size
s= sample standard deviation
= Critical t-value for n-1 degrees of freedom
We assume the family size is normal distributed.
Given, n= 31 , , s= 1.42 ,
Critical t value for and degree of 30 freedom
= 1.697 [By t-table]
The required confidence interval:
Hence, the 90% confidence interval for the estimate = (2.67, 3.53)