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2 years ago

8

Help me please ASAP- do not put any fake answers.... ty:)))

1 answer:

BartSMP [9]2 years ago

8 0

The answer is 4 and 3. 4 for the x axis and 3 for the y axis

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Select the expressions that are equivalent to 4(m+9).

Marianna [84]

Answer:

4m+9

Step-by-step explanation:

4(m+9)

4m+9

4(m+9)=4m+9

3 0

3 years ago

Read 2 more answers

HELP PLEASE???!!!!!!!

Fiesta28 [93]

Answer:

<h2>A. (-4, -15)</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=\dfrac{3}{4}x-12&(1)\\y=-4x-31&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\\dfrac{3}{4}x-12=-4x-31\qquad\text{multiply both sides by 4}\\\\3x-48=-16x-124\qquad\text{add 48 to both sides}\\\\3x=-16x-76\qquad\text{add}\ 16x\ \text{to both sides}\\\\19x=-76\qquad\text{divide both sides by 19}\\\\x=-4\\\\\text{Put it to (2):}\\\\y=-4(-4)-31\\y=16-31\\y=-15$

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3 years ago

Can somebody help with my 2 way table assignments..? i know some of you will take this as a fre.e points question and i don't re

pishuonlain [190]

Answer:

what is the question

Step-by-step explanation:

6 0

3 years ago

3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

$2x + 3(x + 2) = 2(x + 4) + 55$

$= > 2x + 3x + 6 = 2x + 8 + 55$

Eliminating 2x from both the sides,

$= > 3x + 6 = 63$

$= > 3x = 63 - 6 = 57$

$= > x = \frac{57}{3} = 19$

So, the consecutive odd integers are = 19 , 21 & 23.

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2 years ago

In Algebra, we learn about functions of various types. These functions are often seen in a progression from least complicated (l

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3 years ago