First, convert R percent to r a decimal
r = R/100
r = 7%/100
r = 0.07 per year,
Then, solve our equation for A
A = P(1 + r/n)nt
A = 200.00(1 + 0.005833333/12)(12)(5)
A = $ 283.53
Summary:
The total amount accrued, principal plus interest,
from compound interest on an original principal of
$ 200.00 at a rate of 7% per year
compounded 12 times per year
over 5 years is $ 283.53.
Interset always positive ,if a bank don't give interest even though interset remains zero doesn't become negative
Let's find interest here to proof
- Principal=P=48750
- Annual=A=49975
Interest:-
Write it in descending order of degree
that is
-g^3 + 6g^2 + 4g - 9
<h3>The solution is (x, y) = (3, -24)</h3>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x - y = 15 -------- eqn 1
y = -8x ------ eqn 2
We have to find solution of (x, y)
We can solve by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
-3x - (-8x) = 15
-3x + 8x = 15
5x = 15
Divide both sides by 5
<h3>x = 3</h3>
Substitute x = 3 in eqn 2
y = -8(3)
<h3>y = -24</h3>
Thus solution is (x, y) = (3, -24)
Answer:

If we divide both sides by
we got:

And we can use the normal distribution table or excel to find the probabilites and we got:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:
Where
and 
We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean
is given by:

And we want to find this probability:

If we divide both sides by
we got:

And we can use the normal distribution table or excel to find the probabilites and we got:
